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ioda
3 years ago
12

Rita get paid $16 per hour for the first 8 hour she works each day.She earned 1and 1/2 times her hourly pay rate for the first t

ime she works over 8 hours each day.Ritas work day for Monday is describes the list. Worked from 8:15 a.M to 12:45p.M.Took a 45 minutes lunch break.Worked until 6:15 p.M rita does not get paid for her lunch break.How much money did rita earn for the first time she worked on monday?
Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

Rita's pay for Monday is $158.

Step-by-step explanation:

Rita's hourly pay for an 8-hour shift she works everyday is, $16.

If she works overtime she gets paid 1.5 times her hourly pay for every extra hour.

That is, if she works (8 + <em>x</em>) hours a day then the pay for the <em>x</em> hour is, 1.5<em>x</em>.

Rita's working hours on Monday is:

  • Started from 8:15 AM to 12:45 PM ⇒ 4 hours 30 minutes.
  • 45 minutes lunch break ⇒ 12:45 PM + 45 minutes = 1:30 PM
  • Worked from 1:30 PM to 6:15 PM ⇒ 4 hours 45 minutes

It is provided that Rita does not get paid for lunch hour.

Rita's pay for Monday is computed as follows:

= (8:15 AM - 12:45 PM) + (1:30 PM - 6:15 PM)

= (4 hours 30 minutes) + (4 hours 30 minutes)

= (4 + 4) hours + (30 + 45) minutes

= (8 × 16) + (75 minutes × 16 × 1.5)

= 128 + (1.25 hours × 24)

= 128 + 30

= 158

Thus, Rita's pay for Monday is $158.

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Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

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