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Nat2105 [25]
3 years ago
6

Can you please help​

Mathematics
1 answer:
Darina [25.2K]3 years ago
7 0

Answer:

c

Step-by-step explanation:

A number that can be written as a decimal that neither repeats nor terminates.

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Please help whats the answer !!
STALIN [3.7K]
Yes, they are proportional. if you divide the second fraction down to simplest form, you get 7/12, which is equal to the first fraction.
3 0
3 years ago
Marcus is making cookies. The recipe says 214 cups of flour are needed for each batch. Marcus wants to make 3 batches of cookies
Valentin [98]

Answer:

642 Cups of Flower

214 × 3 = 642


8 0
3 years ago
Read 2 more answers
What is the simplified form of the following expression? 2 Sqrt 18+3 Sqrt 2 + Sqrt 162
grandymaker [24]

Answer:

18√2

Step-by-step explanation:

2√18 + 3√2 + √162

= 2√(9 * 2) + 3√2 + √(81 * 2)

= (2 * 3)√2 + 3√2 + 9√2

= 6√2 + 3√2 + 9√2

= (6 + 3 + 9)√2

= 18√2

6 0
3 years ago
Read 2 more answers
Jim wants to build a rectangular parking lot along a busy street but only has 2400 feet of fencing available. if no fencing is r
PSYCHO15rus [73]
<span>Length = 1200, width = 600
   First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as: W = (2400 - L)/2
   And area is: A = LW
    Substitute the equation for width, giving: A = LW A = L(2400 - L)/2
    And expand: A = (2400L - L^2)/2 A = 1200L - (1/2)L^2
    Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
   A = 1200L - (1/2)L^2
 A = 1200(1200+e) - (1/2)(1200+e)^2
 A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
 A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
 A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
 A = 720000 - (1/2)e^2
   And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
7 0
3 years ago
What is "A number decreased by 4 is less than 14" written as an inequality?
navik [9.2K]

Answer:

"A number decreased by 4 is less than 14" written as an inequality is x - 4 < 14

Step-by-step explanation:

First: Figure out what a number decreased by 4 is.

Well, a number decreased by 4, how would that look like? To find out, we should look for some key words in the term. So, I will bold out the keywords in the term this time:

A number decreased by 4

That word 'decreased' gives us a hint. Out of the four basic operations (addition, subtraction, multiplication and division), 'decreased' fits into the subtraction category best. So we can replace 'decreased' with a minus sign. Since we don't know the specific value of 'A number', we will assign it a variable, the variable x. 4 is just 4 so we can leave that number alone. So the first term would look like this:

A number decreased by 4 = x - 4

Second: Since we know what the first term is, we need to find out what the second term is and the inequality sign.

This step is quite easy. Let's tackle the inequality sign first:

A number decreased by 4 is less than 14

The only words that would describe an inequality sign are the words: 'less than'. The less than sign looks like this: <

Fourteen [just like four] is just a number so we don't need to change that

So our final product is this: x - 4 < 14

Thank you for reading.

Topic: Inequalities

6 0
3 years ago
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