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3 years ago

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Here are the test scores for 8 students in Mr. P's class. 58, 82, 43, 73, 90, 37, 62, 75 What is the percentage of these test sc

ores that are less than 73?

1 answer:

Zigmanuir [339]3 years ago

7 0

There are 8 test scores and 4 of them are lower than 73. 4/8 = .5 or 50%
So 50% of these test scores are less than 73.

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Solve the inequality.<br><br> 5/6t - 3≥3t + 6

Papessa [141]

Answer:

t ≤ $-\frac{54}{13}$

Step-by-step explanation:

$\frac{5}{6}$ t−3−3t≥3t+6−3t

$-\frac{13}{6}$ t−3≥6

- $\frac{13}{6}t$ −3+3≥6+3

$\frac{13}{6}$ t≥9

$-\frac{6}{13}$ ( $-\frac{13}{6}$ t) ≥ $-\frac{6}{13}$ (9)

t ≤ $-\frac{54}{13}$

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2 years ago

When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression?

alisha [4.7K]

0.5(20x - 50y + 36) - 0.25(-100x + 40y - 12)
10x - 25y + 18 + 25x - 10y + 3
35x - 35y + 21

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4 years ago

Find the percentage of decrease from 95 to 60

balu736 [363]

The answer is about 36.9%
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So .3685×95 is the closest to equaling 35

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3 years ago

Which equation demonstrates the additive identity property?

Bezzdna [24]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

0o 0 = 0 0 o =

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3 years ago

Read 2 more answers

Help please!!!!!!!!!!

ladessa [460]

Hi! This is a difficult problem because I'm not too familiar with exponential functions but I think that 4^x is an exponential function and 2 multiplied by it means that it's multiplying by an exponential function. Does it make the whole rule exponential? I'm not sure but I don't think it does.

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3 years ago