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Leona [35]
3 years ago
12

How Mendeleev's systematic approach resulted in the development of his Periodic Table of elements.

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
I just wanna know what does that even mean
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Mark as brainlist asap plz <br><br><br><br><br><br> i need the answer asap
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Please mark as brainliest
Emily
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3 years ago
In the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl, if 6 moles of fecl2 are added to 6 moles of naoh, how many moles of fecl2 woul
pychu [463]
The balanced chemical reaction would be 

<span>fecl2 + 2naoh =  fe(oh)2(s) + 2nacl

Initial amounts of the reactants are given, so, we need to determine which of the reactants is the limiting reactant and use this amount to determine what is asked. However, what is being asked is how many of the FeCl2 is used in the reaction, showing that it is NaOH that is the limiting reactants. Thus, we just use the initial amount of NaOH and relate the substances by the chemical reaction as follows:

6 mol NaOH ( 1 mol FeCl2 / 2 mol NaOH ) = 3 mol FeCl2

Therefore, 3 moles of FeCl2 is used up and 3 moles of FeCl2 is also left after the reaction.</span>
5 0
3 years ago
Read 2 more answers
How many molecules is 0.360 mole of water?
Nikitich [7]

Answer: 2.17 x 10^23 molecules

Explanation:

1mole of H2O contains 6.02x10^23 molecules.

Therefore 0.360mole of H2O will contain = 0.36 x 6.02x10^23 = 2.17 x 10^23 molecules

4 0
3 years ago
La luna es materia? ayuda pisos es para yaaaaaaa!! ;)​
Valentin [98]

Answer:

La Luna ? Deberia ser materia

Explanation:

6 0
3 years ago
Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
             Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.

<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
                   Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
5 0
3 years ago
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