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topjm [15]
3 years ago
12

William adds two values, following the rules for using significant figures in computations. He should write the sum of these two

numbers by using
Chemistry
2 answers:
Alinara [238K]3 years ago
7 0
It seems that you have missed the necessary options for us to answer this question, but anyway here is the answer. William adds two values, following the rules for using significant figures in computations. He should write the sum of these two numbers by using the same number of decimal places as the least precise value. Hope this helps.
ella [17]3 years ago
7 0

the answer is A GEEEZ !!!!!!!


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Please help it’s a test due in five minutes! I’ll give 10 points
barxatty [35]

Answer: negative acellaration or mass.

Explanation:

the first reason why is that i got that quistion right. and when objects are unbalanced it gives negative acellaration

3 0
3 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
3 years ago
WHAT IS THE STOCK NAME FOR FeSO^3
podryga [215]
Feso3 compound name

Iron(II) Sulfite FeSO3 Molecular Weight

Hope this helps!

Have a great day :)
4 0
3 years ago
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
Do you think there should be greater restrictions on who can buy explosives or accelerants? Why or why not?
fgiga [73]
In my opinion yes, as of now, almost anyone could get there hands on lets say an explosive. Have you heard of dynamite fishing? It is illegal, but it is still done once people have access to dynamite, then what ends up happening not only do marine wildlife get killed but it pollutes the water and lessens the chance of the natural cycle of life. Also there are several other factors, firstly, what will you do with an explosive once you get your hands on it? Perhaps you could just use an explosive for fun/personal entertainment...that isn't right and it could harm people. So, to conclude the harder it is for people to access explosives or even acclerants the better...and to add this can be possible by making people get like some sort of licence to use them, and let them be trained in certain conditions so that there is no regrets once they have access to them. I know my idea sounds far fetched but its a thought!
4 0
3 years ago
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