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Novosadov [1.4K]
4 years ago
11

Which of these statements best explains why the ocean currents in the Northern hemisphere tend to move in the clock-wise directi

on? (2 points) Question 14 options: 1) The currents deflect to the right due to the rotation of Earth. 2) The change in gravitational forces causes currents to move towards right. 3) The deflection of winds to the left causes the currents to move in the opposite direction. 4) The altered wind speed due to Earth's rotation causes the movement of ocean water.Which of these statements best explains why the ocean currents in the Northern hemisphere tend to move in the clock-wise direction? (2 points) Question 14 options: 1) The currents deflect to the right due to the rotation of Earth. 2) The change in gravitational forces causes currents to move towards right. 3) The deflection of winds to the left causes the currents to move in the opposite direction. 4) The altered wind speed due to Earth's rotation causes the movement of ocean water.
Chemistry
1 answer:
Evgesh-ka [11]4 years ago
6 0

Answer: Option (1) is the correct option that is currents deflect to the right due to the rotation of Earth.

Explanation:

The water on the surface of ocean is moved by winds that blow in certain direction because of the Coriolis effect and spinning of the Earth that's why ocean currents in the Northern hemisphere tend to move in the clock-wise direction.

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Answer:

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

<em>Where X is cation and Y is anion.</em>

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. <em>Where X is the solubility of the compound.</em>

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

S = \sqrt[2]{\frac{1.8x10^{-10}}{1} } = 1.34x10⁻⁵M

S = \sqrt[3]{\frac{1.1x10^{-12}}{4} } = 6.50x10⁻⁵M

S = \sqrt[2]{\frac{5.4x10^{-13}}{1} } = 7.35x10⁻⁷M

S = \sqrt[2]{\frac{8.5^{-17}}{1} } = 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

<em>AgI, AgBr, AgCl and Ag₂CrO₄</em>

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