The % composition when 10g of magnesium combine with 4g of nitrogen is 71.43% magnesium and 28.57 % nitrogen
calculation
% composition = mass of an element / total mass x100
mass of magnesium = 10 g
mass of nitrogen = 4g
calculate the total mass used
= 10g of Magnesium + 4 g of nitrogen = 14 grams
% composition for magnesium is therefore = 10/14 x100 = 71.43 %
% composition for nitrogen is therefore = 4 /14 x100 = 28.57 %
CBr4 is a symmetric tetrahedral molecule so it will be non-polar.
Answer:
Reference image attached
Explanation:
Please see the attached image.
Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol
moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles
calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
therefore the emipical formula = CaSO4
The organic compounds that are divided into two types, simple and complex, are called carbohydrates.
Carbohydrates are diveded into twy types: simple and complex (starches, fiber, glycogen).
Simple carbohydrates are made of one (monosaccaharides) or two sugar units.
Complex carbohydrates are made up of many sugar units.
For example, glucose (C₆H₁₂O₆) is a simple carbohydrate.
Glucose is chemical compound composed of six carbon atoms, twelve hydrogen atoms and six oxygen atoms.
Starch is a polymeric carbohydrate consisting of a large number of glucose units bonded by glycosidic bond. Starch is a white, tasteless and odorless powder that is insoluble in cold water or alcohol.
More about carbohydrates: brainly.com/question/20290845
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