Answer: The new concentration of a solution of 
is 0.2 M 10.0 mL of a 2.0 M solution is diluted to 100 mL.
Explanation:
Given: 
= 10.0 mL, 
= 2.0 M
= 100 mL, 
= ?
Formula used to calculate the new concentration is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new concentration of a solution of is 0.2 M 10.0 mL of a 2.0 M solution is diluted to 100 mL.
The total Pressure equals the sum of all pressures contained
<span>Since total pressure and the pressure of nitrogen and oxygen is given, finding the pressure of carbon dioxide is given by: </span>
<span>Pressure of Carbon dioxide = 42.9- 6.6- 23.0 </span>
<span>=13.3kPa </span>
The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
Learn more about molarity:
brainly.com/question/15370276
Answer:
The answer to your question is E = 83.2 J
Explanation:
Data
Element: Gold
Initial temperature = T1 = 5°C
Final temperature = T2 = 37°C
mass = 20 g
Specific heat = 130 J/kg°K
Process
1.- Convert temperature to kelvin
T1 = 273 + 5 = 278°K
T2 = 273 + 37 = 310°K
2.- Convert mass to kg
1000 g --------------- 1 kg
20 g --------------- x
x = (20 x 1)/1000
x = 0.02 kg
3.- Formula
E = mC(T2 -T1)
4.- Substitution
E = (0.02)(130)(310 - 278)
E = (0.02)(130)(32)
E = 83.2 J
