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Mazyrski [523]
3 years ago
14

Another way to write 9 x 200

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
6 0
200+200+200+200+200+200+200+200+200
djyliett [7]3 years ago
6 0

Answer:

Since, Multiplication is a shortcut for addition.

Use of Distributive Property is the most familiar alternative way to write 9 x 200.

Distributive Property states that when a number is multiplied by the sum of two numbers, then the  first number can be distributed to both of those numbers and multiplied by each of them separately i.e,

a \times (b+c) =a\times b +a\times c

9 x 200

First replace 200 as 100+100 then, we have

9 \times (100+100)

Now, using distributive property above:

9 x 200 = 9 \times (100+100) =(9 \times 100)+ (9 \times 100) = 900+900 =1800.



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Part of the area under this ramp serves for storage. Items can be stored only in the unshaded part of the ramp
Mekhanik [1.2K]

Answer:

48.1 m³ available, 2.5m³ not available

Step-by-step explanation:

Tan(X) = 4.5/(5.8+1.7)

Tan X = 3/5

Hypotenuse² = 3² + 5² = 34

Sin X = 3/sqrt(34)

X = 30.96

1/sinX = 1.7/SinY

Y = 61.003°

Third angle: 180 - X - Y = 88.037

Volume

= ½ × 1.7 × 1 × sin(88.038) × 3

= .

= 2.548

= 2.5m³

Available for storage:

½×4.5×7.5×3 - 2.548

= 48.077 = 48.1 m³

7 0
3 years ago
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
A dressmaker needs to cut 9-inch pieces of ribbon from rolls of ribbon that are 6 feet
Nikolay [14]
It will be 14 we calculated
8 0
3 years ago
Need help with 6 dont know it
pickupchik [31]

Answer:

It should be 42.25 instead

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Roberta has $10,540 to invest. She plans to invest her money in certificates of deposit (CDs) that have 2.1% interest, a stock p
ira [324]

Answer:

The amount invested in CDs is  $1,340

The amount invested in the stock portafolio is $6,900

The amount invested in the saving accounts is $2,300

Step-by-step explanation:

Let

x ---->the amount invested in CDs at 2.1%

y ---> the amount invested in the stock portfolio at 2.5%

z ---> the amount invested in the savings account at 1.5%

x+y+z=10,540 ----> equation A

z=\frac{1}{3}y ----> equation B

substitute equation B in equation A

x+y+\frac{1}{3}y=10,540

x+\frac{4}{3}y=10,540

x=10,540-\frac{4}{3}y ----> equation C

we know that

The total interest earned by the three amount must be equal to $231.69

so

0.021x+0.025y+0.015z=231.69 ----> equation D

substitute equation B and equation C in equation D

0.021(10,540-\frac{4}{3}y)+0.025y+0.015(\frac{1}{3}y)=231.69

solve for y

221.34-0.0315y+0.025y+0.005y=231.69

0.0015y=231.69-221.34

0.0015y=10.35

y=\$6,900

<em>Find the value of x</em>

x=10,540-\frac{4}{3}(6,900)

x=\$1,340

<em>Find the value of z</em>

z=\frac{1}{3}(6,900)

z=\$2,300

7 0
3 years ago
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