Answer:
No. A
Explanation:
cause due to the friction between both molecules heat is produced rapidly.
Polar covalent bonds (because hydrogen and oxygen form polar bonds and are both nonmetals so it's covalent) and hydrogen bonds (because the water molecules are attracted to each other with partial charges, causing specific properties like surface tension).
So in my very bad drawing that I attached in case you're more a visual learner, the d- and d+ show the partial charges of hydrogen and oxygen (making it polar, as the electrons in the bond are more shifted towards oxygen, which is why oxygen has a negative sign) and the yellow dotted line show the hydrogen bonds.
Answer:
part 1
3) 5.47 molecules
4) 11.15 moles
5) 2.95 × 10^23 molecules
6) 7670.9g
part2
1) 216000g
2) 5.71 molecules
3) 0.18 moles
4) 737.40g
5) 2.89×10^23 molecules
Explanation:
part 1
3) number of moles = (6.02 × 10^23)/11.0
=5.47molecules.
4) moles= (6.02 × 10^23)/(5.40×10^23)
= 11.15 moles
5) molar mass of NH3= 14+(3×1)= 14+3=17
number of molecules= (6.02 × 10^23) × 17/35
= (6.02 × 10^23)× 0.49 =2.95 × 10^23 molecules
6) molar mass of N2I6= (2×14) + (6×127)
= 28+762= 790g/mol
mass= 790 × (6.02 × 10^23)/(6.20×10^22)
=790× 9.71= 7670.9g
part 2
1) molar mass of CuBr= 64+80= 144g/mol
mass= 1500 × 144= 216000g
2) molecules = (6.02 × 10^23)/1.055
= 5.71 molecules
3) moles = (6.02 × 10^23)/(3.35×10^24)
= 0.18 moles
4) molar mass of SiO2= 28+ (2×16)= 28+32
=60gmol
mass= 60 × (6.02 × 10^23)/(4.90×10^22)
= 60× 12.29= 737.40g
5) molar mass of CH4= 12+(4×1)= 12+4=16g/mol
number of molecules= (6.02 × 10^23) × 16/33.6
= (6.02 × 10^23)× 0.48
= 2.89×10^23 molecules
Answer:
leading zeroes to the left of a decimal point. and trailing zeros to the left of an invisible decimal point.
Explanation:
- All nonzero digits are significant figures. Example: 713 has three significant figures. 18,991 has five significant figures.
- Zeros located between two nonzero digits are significant figures. Example: 505 has three significant figures. 17,009 has five significant figures.
- Zeros at the ends of numbers are only significant if there is a decimal point in the number. Example: 502.00 has five significant figures (5,0,2,0,0). 5020 has three significant figures (5,0,2) 100,000 has one significant figure (1)
- Zeros that come before the first nonzero digit are not significant. Example: 0.0007 has one significant figure (7). 0.0970 has three significant figures (9,7,0)