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irinina [24]
3 years ago
10

A solution of Na2CO3 is added dropwise to a solution that contains 1.12×10−2 M Fe2+ and 1.45×10−2 M Cd2+. What concentration of

CO32− is need to initiate precipitation? Neglect any volume changes during the addition.
Chemistry
1 answer:
aalyn [17]3 years ago
8 0

Answer:

The cadmium carbonate (CdCO3) will precipitate first.

We need 6.9 *10^-11 M CO3^2- to initiate precipitation.

Explanation:

<u>Step 1:</u> Given data

The solution contains

 ⇒ 1.12*10^-2 M Fe2+

 ⇒ 1.45*10^−2 M Cd2+

The Ksp of CdCO3 is 10^-12

The Ksp of FeCO3 is 3.13 * 10^-11

<u>Step 2:</u> Calculate concentration of CO3^2- in FeCO3

FeCO3(s) ⇔ Fe2+ + CO3^2-       Ksp = 3.1*10^-11

Ksp = [Fe2+][CO3^2-]

[CO3^2-] = Ksp / [Fe2+]

[CO3^2-] = 3.13*10^-11 / 1.12*10^-2

[CO3^2-] = 2.795 * 10^-9 M

<u>Step 3:</u> Calculate concentration of CO3^2- in CdCO3

CdCO3(s) ⇔Cd^2+ + CO3^2-            Ksp = 10^-12

Ksp = [Cd2][CO3^2-]

[CO3^2-] = Ksp /[Cd^2+]

[CO3^2-] =  10^-12 / 1.45x10^-2

[CO3^2-] =6.9 *10^-11 M

The cadmium carbonate (CdCO3) will precipitate first.

We need 6.9 *10^-11 M CO3^2- to initiate precipitation.

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The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

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<h3>Final volume (V₂) =? </h3>

  • The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

V_{2} = \frac{58752}{4023}\\\\

<h3>V₂ = 15 L </h3>

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Learn more: brainly.com/question/25547148

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