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irinina [24]
3 years ago
10

A solution of Na2CO3 is added dropwise to a solution that contains 1.12×10−2 M Fe2+ and 1.45×10−2 M Cd2+. What concentration of

CO32− is need to initiate precipitation? Neglect any volume changes during the addition.
Chemistry
1 answer:
aalyn [17]3 years ago
8 0

Answer:

The cadmium carbonate (CdCO3) will precipitate first.

We need 6.9 *10^-11 M CO3^2- to initiate precipitation.

Explanation:

<u>Step 1:</u> Given data

The solution contains

 ⇒ 1.12*10^-2 M Fe2+

 ⇒ 1.45*10^−2 M Cd2+

The Ksp of CdCO3 is 10^-12

The Ksp of FeCO3 is 3.13 * 10^-11

<u>Step 2:</u> Calculate concentration of CO3^2- in FeCO3

FeCO3(s) ⇔ Fe2+ + CO3^2-       Ksp = 3.1*10^-11

Ksp = [Fe2+][CO3^2-]

[CO3^2-] = Ksp / [Fe2+]

[CO3^2-] = 3.13*10^-11 / 1.12*10^-2

[CO3^2-] = 2.795 * 10^-9 M

<u>Step 3:</u> Calculate concentration of CO3^2- in CdCO3

CdCO3(s) ⇔Cd^2+ + CO3^2-            Ksp = 10^-12

Ksp = [Cd2][CO3^2-]

[CO3^2-] = Ksp /[Cd^2+]

[CO3^2-] =  10^-12 / 1.45x10^-2

[CO3^2-] =6.9 *10^-11 M

The cadmium carbonate (CdCO3) will precipitate first.

We need 6.9 *10^-11 M CO3^2- to initiate precipitation.

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'Synthetic detergents are better than soaps'. Justify this statement​
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Karl likes to use cruise control when he drives on
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Answer:

3.96 MINUTES

Explanation:

Karl likes to use cruise control when he drives on

the highway. After setting cruise control at 33.53

m/s (75 mph). At this speed, how long would it

take Karl to travel 8 kilometers?

VELOCITY = DISTANCE/TIME

OR

V=D/T

SO

VT=D

SO

T=D/V

THE DISTANCE IS 8 KM

THE VELOCITY IS 75 MPH

THERE ARE 1.61 KM PER MILE

SO

75M[H =

75 X 1.61 KM/H =

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T=D/V

T=8/121 =0.066 HOUR =

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3 0
2 years ago
A sample of gaseous methyl ether has a mass of 8.12g and occupies a volume of 3.96L at STP. What is the molecular weight of meth
Naya [18.7K]
Molar volume is when 1 mol of any gas occupies 22.4 L at STP.
Methyl ether has a mass of 8.12 g,
Volume occupied - 3.96 L
If 22.4 L occupied by 1 mol of gas
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The mass of 0.176 mol = 8.12 g
Molar mass is mass of 1 mol
Therefore mass of 1 mol = 8.12/0.176 = 46.1
Molecular weight is 46.1 g/mol
5 0
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