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irinina [24]
3 years ago
10

A solution of Na2CO3 is added dropwise to a solution that contains 1.12×10−2 M Fe2+ and 1.45×10−2 M Cd2+. What concentration of

CO32− is need to initiate precipitation? Neglect any volume changes during the addition.
Chemistry
1 answer:
aalyn [17]3 years ago
8 0

Answer:

The cadmium carbonate (CdCO3) will precipitate first.

We need 6.9 *10^-11 M CO3^2- to initiate precipitation.

Explanation:

<u>Step 1:</u> Given data

The solution contains

 ⇒ 1.12*10^-2 M Fe2+

 ⇒ 1.45*10^−2 M Cd2+

The Ksp of CdCO3 is 10^-12

The Ksp of FeCO3 is 3.13 * 10^-11

<u>Step 2:</u> Calculate concentration of CO3^2- in FeCO3

FeCO3(s) ⇔ Fe2+ + CO3^2-       Ksp = 3.1*10^-11

Ksp = [Fe2+][CO3^2-]

[CO3^2-] = Ksp / [Fe2+]

[CO3^2-] = 3.13*10^-11 / 1.12*10^-2

[CO3^2-] = 2.795 * 10^-9 M

<u>Step 3:</u> Calculate concentration of CO3^2- in CdCO3

CdCO3(s) ⇔Cd^2+ + CO3^2-            Ksp = 10^-12

Ksp = [Cd2][CO3^2-]

[CO3^2-] = Ksp /[Cd^2+]

[CO3^2-] =  10^-12 / 1.45x10^-2

[CO3^2-] =6.9 *10^-11 M

The cadmium carbonate (CdCO3) will precipitate first.

We need 6.9 *10^-11 M CO3^2- to initiate precipitation.

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The diameter of the He He atom is approximately 0.10 nm nm . Calculate the density of the He atom in g/cm 3 g/cm3 (assuming that
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Answer:

Density of the He atom = 12.69 g/cm³

Explanation:

From the information given:

Since 1 mole of an atom = 6.022x 10²³ atoms)

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The volume can be determined as  folows:

since the diameter of the He atom is approximately 0.10 nm

the radius of the He = \dfrac{0.10}{2} = 0.05 nm

Converting it into cm, we have:

0.05 nm \times  \dfrac{10^{-9} \  meters}{ 1  nm} \times \dfrac{ 1 cm }{10^{-2} \ meters}

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Assuming that it is a sphere, the volume of a sphere is

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= \dfrac{4}{3}\pi  \times (5\times 10^{-9})^3

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Finally, the density can be calcuated by using the formula :

Density = \dfrac{mass}{volume}

D =  \dfrac{6.647 \times  10^{-24} \  grams }{ 5.236 \times 10^{-25} \  cm^3}

D = 12.69 g/cm³

Density of the He atom = 12.69 g/cm³

4 0
3 years ago
Read 2 more answers
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