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Natali5045456 [20]
4 years ago
10

Begin with a question. What is something you want to know about free fall?

Chemistry
1 answer:
Phoenix [80]4 years ago
5 0

Answer:

In free fall, an object moves under the influence of gravitational forceonly. The only acceleration is the acceleration of gravity g. No other force, including air resistance, is acting on such an object. Interestingly, an object in free fall doesn't necessarily need to be falling (that is, moving downwards).

Explanation:

You might be interested in
A substance that changes color when placed in an acidic or basic solution is called a
GREYUIT [131]
PH is your answer

Hope this helps!!
7 0
4 years ago
For the reaction of hydrogen with iodine
fenix001 [56]

Answer:

r_{H_2} = \frac{-1}{2} r_{HI}

Explanation:

Hello!

In this case, considering the given chemical reaction:

H_2(g) + I_2(g) \rightarrow 2HI(g)

Thus, by applying the law of rate proportions, we can write:

\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

r_{H_2} = \frac{-1}{2} r_{HI}

Best regards!

8 0
3 years ago
6 How many moles are in a 321 g sample of magnesium?
Tatiana [17]

Answer:

13.4mol of Mg

Explanation:

Given parameters:

Mass of magnesium = 321g

Unknown:

Number of moles  = ?

Solution:

The number of moles of a substance is given as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of Mg = 24g/mol

 Insert the parameters and solve;

        Number of moles  = \frac{321}{24}   = 13.4mol of Mg

3 0
3 years ago
My insta Aj.lil.Sparks
Anika [276]

Answer:

ok cool

Explanation:

5 0
3 years ago
Read 2 more answers
In titrating 0.20 M hydrochloric acid, HCl, with 0.20 M NaOH at 25°C, the solution at the equivalence point is
xxTIMURxx [149]

Answer:

c) 0.10M NaCl

Explanation:

<em>Options are:</em>

<em>a) 0.20M NaCl</em>

<em>b) Very acidic</em>

<em>c) 0.10M NaCl</em>

<em>d) 0.10M HCl + 0.20M NaOH</em>

<em>e) Slightly acidic.</em>

<em />

Based on the reaction:

NaOH + HCl → H₂O + NaCl

You can see than 1 mole of NaOH reacts per mole of HCl producing 1 mole of NaCl

Assuming 1L of 0.20M HCl reacts with 1L of NaOH, moles of both compounds are:

1L * 0.20mol/L = 0.20 moles reacts. That means moles of NaCl produced are 0.20moles in 2L. Molarity of NaCl is:

0.20mol / 2L = 0.10M NaCl

That means, right option is:

<h3>c) 0.10M NaCl</h3>

8 0
3 years ago
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