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saveliy_v [14]
3 years ago
7

Helpppppoop. Question 6 of 10

Chemistry
1 answer:
oee [108]3 years ago
7 0
D solid





Ok there you go
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To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber
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Answer:

The volume of the gas at given temperature is 1300 cm^3

Explanation:

P_1 = initial pressure of gas = 1 atm

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(1 cm^3= 1mL , 1 mL = 0.001 L)

P_1V_1=nRT_1..[1]

P_2 = final pressure of gas = 2.1 atm

T_2 = final temperature of gas = 2,200^oC=273+2200 K=2473.15 K

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By dividing [1] and [2] we get combined gas equation :,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

Now put all the given values in the above equation, we get:

V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}

V_2=1.3 L=1300 mL= 1300 cm^3

The volume of the gas at given temperature is 1300 cm^3

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