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saveliy_v [14]
2 years ago
7

Helpppppoop. Question 6 of 10

Chemistry
1 answer:
oee [108]2 years ago
7 0
D solid





Ok there you go
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When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2AlCl3 ( aq ) +
Rufina [12.5K]

Answer:

The answer to your question is  V = 19.9 L

Explanation:

Data

mass of Al = 8.60 g

volume of H₂ = ?

Balanced chemical reaction

                 2Al  +  6HCl  ⇒   2AlCl₃  +  3H₂

1.- Use proportions to calculate the mass of H₂ produced

Atomic mass of Al = 2 x 27 = 54 g

Atomic mass of H₂ = 6 x 1 = 6 g

                54 g of Al -------------------- 6 g of H₂

                  8 g  of Al -------------------  x

                  x = (8 x 6) / 54

                  x = 48 / 54

                  x = 0.89 g of H₂

2.- Calculate the volume of H₂

- Convert the H₂ to moles

                    1 g of H₂ --------------- 1 mol

                   0.89 g    ---------------- x

                    x = 0.89 moles

                    1 mol of H₂ -------------- 22.4 l

                   0.89 moles  ------------- x

                    x = (0.89 x 22.4) / 1

                   x = 19.9 L                        

6 0
2 years ago
What is an alloy?<br> Answer question 2 if you want.
Anna11 [10]

Answer:

An alloy is a combination of metals or metals combined with one or more other elements. For example, combining the metallic elements gold and copper produces red gold, gold and silver becomes white gold, and silver combined with copper produces sterling silver. Elemental iron, combined with non-

Explanation:

that's what an alloy is all the rocks including gold silver combined with copper  and sterling silver

7 0
3 years ago
Read 2 more answers
A sample of a gas is kept at constant pressure while
Ahat [919]

Explanation:

here's the answer to your question

5 0
2 years ago
An obese man was discovered in his air-conditioned hotel room sitting in a chair in front of the television. The air conditioner
Leno4ka [110]

Answer:

It has been approximately 6 hours after death.

Explanation:

This is because between 2-6 hours after death, the body starts becoming stiff from top to bottom, then spreading to the limbs. Since there is only rigor in his upper body, that would mean that with normal temperature and body conditions, it would be 4 or 5 hours after death. But since he is obese and in cold temperature, there is slower progression of rigor, leading to the maximum time in the first rigor mortis phase, 6 hours.

8 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
2 years ago
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