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Gala2k [10]
3 years ago
14

Which expression is equivalent to the one below?

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0

Answer:

D . 9 .1/13

Step-by-step explanation:

9\div 13 = \frac{9}{13} \\\\9\cdot \frac{1}{13}\\\\=\frac{9}{1}\cdot \frac{1}{13}\\\\=\frac{9\cdot \:1}{1\cdot \:13}\\\\=\frac{9}{13}

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3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third
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Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

2x + 3(x + 2) = 2(x + 4) + 55

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Eliminating 2x from both the sides,

=  > 3x + 6 = 63

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=  > x =  \frac{57}{3}  = 19

So, the consecutive odd integers are = 19 , 21 & 23.

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