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Gala2k [10]
3 years ago
14

Which expression is equivalent to the one below?

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0

Answer:

D . 9 .1/13

Step-by-step explanation:

9\div 13 = \frac{9}{13} \\\\9\cdot \frac{1}{13}\\\\=\frac{9}{1}\cdot \frac{1}{13}\\\\=\frac{9\cdot \:1}{1\cdot \:13}\\\\=\frac{9}{13}

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The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
3 years ago
Can someone please help me on number 16-ABC
melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

<u>Part a) Is x = 0 a solution to both inequalities</u>

FOR  -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

<u>Part b) Is x = 4 a solution to both inequalities</u>

FOR  -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

<u>solving -2x < 10</u>

-2x\:

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)>10\left(-1\right)

Simplify

2x>-10

Divide both sides by 2

\frac{2x}{2}>\frac{-10}{2}

x>-5

-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}

<u>solving -6 < -2x</u>

-6 < -2x

switch sides

-2x>-6

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)

Simplify

2x

Divide both sides by 2

\frac{2x}{2}

x

-6

Thus, the two intervals:

\left(-\infty \:,\:3\right)

\left(-5,\:\infty \:\right)

The intersection of these two intervals would be the solution to both inequalities.

\left(-\infty \:,\:3\right)  and \left(-5,\:\infty \:\right)

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR  -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0
3 years ago
Find the cardinal number for the set. Α = {3, 6, 9, . . . , 36}
Elena-2011 [213]

<em>Hey </em><em>mate!</em><em>!</em>

<em>Answer:</em>

<em>n(</em><em>A)</em><em>=</em><em>1</em><em>2</em>

<em>Solution</em><em>,</em>

<em>A=</em><em>{</em><em>3</em><em>,</em><em>6</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>1</em><em>,</em><em>2</em><em>4</em><em>,</em><em>2</em><em>7</em><em>,</em><em>3</em><em>0</em><em>,</em><em>3</em><em>3</em><em>,</em><em>3</em><em>6</em><em>}</em>

<em>Just </em><em>count </em><em>the </em><em>elements</em><em>,</em>

<em>There </em><em>are </em><em>1</em><em>2</em><em> </em><em>elements </em><em>in </em><em>the </em><em>set.</em>

<em>So </em><em>the </em><em>cardinal </em><em>number </em><em>of </em><em>the </em><em>set </em><em>is </em><em>1</em><em>2</em><em>.</em>

<h2><em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h2>
8 0
2 years ago
Read 2 more answers
If f(x) = 2x2 − 30, find f(4).
Naddik [55]

Just replace x = 4

2x^2 - 30

=2 *(4)^2 -30

= 2 * 16 - 30

= 32 - 30 

= 2

Answer is 2

8 0
2 years ago
Create a pattern for the rule a x +2
geniusboy [140]
X 0 1 2 3 4
Y 2 3 4 5 6
Because in a graph that’s how it’ll be presented
4 0
3 years ago
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