The chances that NEITHER of these two selected people were born after the year 2000 is 0.36
<h3>How to determine the probability?</h3>
The given parameters are:
Year = 2000
Proportion of people born after 2000, p = 40%
Sample size = 2
The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:
P = (1- p)^2
Substitute the known values in the above equation
P = (1 - 40%)^2
Evaluate the exponent
P = 0.36
Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36
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Answer:
(6, - 4)
Step-by-step explanation:
A translation of 4 units right is equivalent to adding 4 to the x- coordinate
A translation of 3 units up is equivalent to adding 3 to the y- coordinate
(x, y) → (x + 4, y + 3) ← translation rule
Hence
(2, - 7) → (2 + 4, - 7 + 3) → (6, - 4)
Answer:
x = 40
Step-by-step explanation:
2x = 4x - 40 (recall properties of a parallelogram)
Solve for x
2x - 4x = 4x - 40 - 4x (subtraction property of equality)
-2x = -40
-2x/-2 = -40/-2 (division property of equality)
x = 20
Answer: - 2/5
Step-by-step explanation: Isolate the vcariable by divding each side by factors that don't contain the variable.
Exact Form: x = - 2/5
Deciaml form: x = -0.4
Hope this helps! :) ~Zane