Graph the solution set to this inequality.<br> 35

Please help me understand.

USPshnik [31]

Answer:

B) 2

Below I wrote the steps on how I would find the answer.

Step-by-step explanation:

1. Yep, so basically cba = cbl + lba.

2. So you need to find x

3. So basically if you set up the equation 61x - 2 = 13x - 1 + 95

4. Then you can solve for x

5. X = 2

5 0

1 year ago

What is the solution set for the open sentence with the given replacement set? x2 + 2 = x + 8, {1, 3, 4, 5}

bonufazy [111]

X^2 + 2 = x + 8
x^2 - x + 2 - 8 = 0
x^2 - x - 6 = 0
Input 1 => 1^2 - 1 - 6 = 1 - 1 - 6 = -6
Input 3 => 3^2 - 3 - 6 = 9 - 3 - 6 = 0
Input 4 => 4^2 - 4 - 6 = 16 - 4 - 6 = 6
Input 5 => 5^2 - 5 - 6 = 25 - 5 - 6 = 14

Solution set { -6, 0, 6, 14}

7 0

3 years ago

A bag contains three red marbles, four blue, nine yellow, and five green. what is the probability of getting a yellow or green

Marina86 [1]

Answer:

14/21 or 2/3

Step-by-step explanation:

66 percent

6 0

3 years ago

Read 2 more answers

Assuming boys and girls are equally likely, find the probability of a couple having a baby boy when their fifth child is born,

GREYUIT [131]

Answer: $\dfrac{1}{2}$

Step-by-step explanation:

If we assume that the boys and girls are equally likely, so the probability of having a girl is equal to probability of having a boy = $\dfrac{1}{2}$ .

Let B = Event of having a boy.

G= Event of having a girl.

Since both events are independent of each other . (Events that do not depends on each other.)

So irrespective of the four baby boy , the probability that the fifth child is a boy = $\dfrac{1}{2}$

Therefore , the probability of a couple having a baby boy when their fifth child is born, given that the first four children were all boys= $\dfrac{1}{2}$

8 0

3 years ago

The angles of depression of two ships from the top of the light house are 45° and 30° towards east. If the ships are 200 m apart

azamat

Answer:

273 meters

Step-by-step explanation:

See image attached for the diagram I used to represent this scenario.

The distance between the ships, at angles 30 and 45, is 200 meters. The distance between the left ship and the lighthouse is x meters.

We can use trigonometric ratios to solve this problem. We can use the tangent ratio $\big{(} \frac{\text{opposite}}{\text{adjacent}} \big{)}$ to create an equation with the two angles.

$\displaystyle \text{tan(45)} = \frac{h}{x}$
$\displaystyle \text{tan(30)} = \frac{h}{x+200} }$

Let's take these two equations and solve for x in both of them.

<h2> $\textbf{Equation I}$ </h2>

$\displaystyle \text{tan(45)} = \frac{h}{x}$

tan(45) = 1, so we can rewrite this equation.

$\displaystyle 1=\frac{h}{x}$

Multiply x to both sides of the equation.

$\displaystyle x = h$

<h2> $\textbf{Equation II}$ </h2>

$\displaystyle \text{tan(30)} = \frac{h}{x+200} }$

Multiply x + 200 to both sides and divide h by tan(30).

$\displaystyle \text{x + 200} = \frac{h}{\text{tan (30)}}$

Subtract 200 from both sides of the equation.

$\displaystyle \text{x} = \frac{h}{\text{tan (30)}} - 200$

Simplify h/tan(30).

$x=\sqrt{3}h - 200$

<h2> $\textbf{Equation I = Equation II}$ </h2>

Take Equation I and Equation II and set them equal to each other.

$h=\sqrt{3}h-200$

Subtract √3 h from both sides of the equation.

$h-\sqrt{3}h=-200$

Factor h from the left side of the equation.

$h(1-\sqrt{3}) =-200$

Divide both sides of the equation by 1 - √3.

$\displaystyle h=\frac{-200}{1-\sqrt{3} }$

Rationalize the denominator by multiplying the numerator and denominator by the conjugate.

$\displaystyle h=\frac{-200}{1-\sqrt{3} } \big{(} \frac{1+\sqrt{3} }{1+\sqrt{3}} \big{)}$
$\displaystyle h=\frac{-200+200\sqrt{3} }{1-3}$
$\displaystyle h =\frac{-200+200\sqrt{3} }{-2}$

Simplify this equation.

$\displaystyle h=100+100\sqrt{3}$
$h=273.20508075$

The height of the lighthouse is about 273 meters.

5 0

2 years ago

Read 2 more answers

Graph the solution set to this inequality. 35 - 1175 + 9