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Alex777 [14]
1 year ago
7

How many ms in a second?

Mathematics
1 answer:
professor190 [17]1 year ago
4 0
1000. its making me type more stuff

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Determine the volume of a cylinder with 251.20cm2 lateral area and 78.50cm2 base area ​
horrorfan [7]

Answer:

Answer is 628 cm^3

Step-by-step explanation:

using base area lets find radius

base area=pie*(r)^2

78.50=3.14*r^2

78.50/3.14=r^2

25=r^2

5=r

now using lateral area lets find height

lateral area=2*pie*r*h

251.20=2*3.14*5*h

251.20=31.4*h

251.20/31.4=h

8=h

volume of cylinder=pie*(r)^2*h

=3.14*(5)^2*8

3.14*25*8

=628 cm^3

3 0
2 years ago
Mr. Meadows has a 6 1⁄2 gallon bucket. His dipping can holds 1 1⁄2 gallons. How many times does he have to dip into the pond wit
svlad2 [7]

Answer:

He has to dip it 5 times

Step-by-step explanation:

each time he dips it, he gets 1 1/2, or 1.5 gallons. how many times can you add 1.5 to 6 1/2, or 6.5. It is 4 1/3 times, but since you can't dip the bucket 1/3 of a time, it is counted as 1, so 5

3 0
2 years ago
Read 2 more answers
Correct Answer will get BRAINLIEST!
frozen [14]

Answer:

The degree measure of ∠ACP is 112.5°

Step-by-step explanation:

The total area of the given diagram is the sum of two semicircles with arc AB and arc CB having radius R and r respectively

Where:

R = AC

r = DB

R = 2 × r

Therefore the area of the semicircles are given as follows;

For the semicircle with arc AB, we have;

Area, A₁ = π × R²/2 = π × (2×r)²/2 = 2×π×r²

For the semicircle with arc CB, we have;

Area, A₂ = π × r²/2 =  1/2×π×r²

The ratio of the two semicircles is presented in the following relation;

\dfrac{A_1}{A_2} = \dfrac{2 \cdot \pi \cdot r^2}{\dfrac{1}{2}  \cdot \pi \cdot r^2} = \dfrac{2}{\dfrac{1}{2} } = 2 \times \dfrac{2}{1}  = 4

Therefore, the area of A₁ is four times that of A₂ or A₁ =  4 × A₂

The total area of the given diagram = A₁ + A₂ = 4 × A₂ + A₂ = 5·A₂

∴ Half of the area of the diagram, A_H = 5·A₂/2 = 2.5·A₂ = 2.5 × 1/2×π×r² = 1.25×π×r²

The ratio of half of the diagram of the figure to the area of the semicircle with arc AB is found as follows;

A_H/A₁ = (1.25×π×r²)/(2×π×r²) = 5/8

Therefore, the half of the diagram of the figure given by segment PAC is equivalent to 5/8 of the semicircle with arc AB

Given that the arc AB subtends an angle of 180° at the center (angle subtended by a semicircle), the arc AP will subtend 5/8×180 = 112.5°

To verify we have;

Area of a segment of a circle is presented in the following relation;

\dfrac{\theta}{360} \times \pi  \times r^2

As segment PAC is 5/8 of a semicircle, it is therefore 5/(8×2) or 5/16 of the whole circle

Hence;

\dfrac{5}{16} \times \pi \times r^2 =  \dfrac{\theta}{360} \times \pi  \times r^2

\dfrac{5}{16} =  \dfrac{\theta}{360}

\theta \dfrac{}{} =  \dfrac{360 \times 5}{16} = 112.5 ^ {\circ}

Therefore the degree measure of ∠ACP is 112.5°.

5 0
3 years ago
In a plane, the lengths of line segments AB, BC, and CD are 3, 5, and 1. If m represents the greatest possible length of line se
coldgirl [10]
8? I think

Srry if im wrong
4 0
2 years ago
Mia went shopping for a new pair of pants because of a sale. The price on the tag was $34, but Mia paid $27.20 before tax. Find
irina1246 [14]

Answer:

0.068%

Step-by-step explanation:

<u>Before</u> is the key word you want to know the price <u>before</u> she tax so you would subtract the two numbers to get your before tax answer 6.8 then you would divided this by 100 to make it a percent

5 0
2 years ago
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