Answer:
Total number of pages in the book is 234.
Step-by-step explanation:
Let us assume that the total number of pages in the book = <em>x</em>
Now, it is given that Makaila read 44 pages yesterday.
Also, Makaila read two-third of the book today. As we have assumed that, there are a total of x number of pages in the book, so we can say that Makaila read two-third of <em>x </em>number of pages today.
Number of pages read by Makaila today = 
Now, it is also given that, Makaila read a total of 200 pages in the past two days.
∴ according to question,
Pages read yesterday + Pages read today = 200
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⇒![132+2x=200\times3\;\;\;\;\;\;\;\;\;[On\;cross-multiplying]](https://tex.z-dn.net/?f=132%2B2x%3D200%5Ctimes3%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5BOn%5C%3Bcross-multiplying%5D)
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∴ Total number of pages in the book = <em>x</em> = 234
You answer should be 8 and 11 maybe I don't know
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
Answer:13.5
Step-by-step explanation:
the answer is 13.5
