Hello there.
<span>Fifty- three students from 32 different schools signed up for a multi-classroom project. About how many students signed up for the project?
</span><span>B. about 1,800 students
</span>
Answer:
therefore the correct options are:
B. the equation is an exponential decay equation.
F. $28000 represents the initial cost of an automobile that depreciates 27% per year over the course of t years.
Step-by-step explanation:
i) the cost of an automobile is given by the equation is
C(t) =
, where C(t) represents the cost and t represents the time in years
ii) the above equation is an exponential decay equation. It is a decay equation because growth rate is 0.73 which is less than 1 and greater than zero.
ii) when t = 0 then the cost is C(0) = 28000 represents the initial cost.
iii) from the equation in i) we can understand that the cost depreciates 27% per year over the course of t years.
therefore the correct options are:
B. the equation is an exponential decay equation.
F. $28000 represents the initial cost of an automobile that depreciates 27% per year over the course of t years.
Answer:
Peter will pay:
- $50 deductible
- 20% x ($1,060 - $50) = $202
- total $252
the insurance company will pay:
- (total counseling cost - deductible) x 80% = ($1,060 - $50) x 80% = $808
The deductible refers to the amount of money an insured has to pay before the health insurance company starts to pay partially or completely for your health treatment. deductibles are commonly used for other types of insurance policies also, including auto insurance.
Answer:
Answer:
4/24
Step-by-step explanation:
Because 1/6 is 4/24 simplified.
To prove this, all you have to do is try simplifying 4/24 yourself. To do that, we are going to use 4 to divide both the numerator and the denominator because 4 is a common factor of 4 and 24.
(To simplify a fraction, you divide both the numerator and denominator by a common factor)
So 4 divided by 4 is 1, and 24 divided by 4 is 6
1/6
99% sure im right ;)
Answer:
Follows are the solution to this question:
Step-by-step explanation:
In the given question some of the data is missing so, its correct question is defined in the attached file please find it.
Let
A is quality score of A
B is quality score of B
C is quality score of C
![\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\](https://tex.z-dn.net/?f=%5Cto%20P%5BA%5D%20%3D0.55%5C%5C%5C%5C%5Cto%20P%5BB%5D%20%3D0.28%5C%5C%5C%5C%5Cto%20P%5BC%5D%20%3D0.17%5C%5C)
Let F is a value of the content so, the value is:
![\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\](https://tex.z-dn.net/?f=%5Cto%20P%5B%5Cfrac%7BF%7D%7BA%7D%5D%20%3D0.15%5C%5C%5C%5C%5Cto%20P%5B%5Cfrac%7BF%7D%7BB%7D%5D%20%3D0.12%5C%5C%5C%5C%5Cto%20P%5B%5Cfrac%7BF%7D%7BC%7D%5D%20%3D0.14%5C%5C)
Now, we calculate the tooling value:
![\to p[\frac{C}{F}]](https://tex.z-dn.net/?f=%5Cto%20p%5B%5Cfrac%7BC%7D%7BF%7D%5D)
using the baues therom:
