Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
3/10
Step-by-step explanation:
(60y-18)=2(8-16)
60y-18=16-16
60y-18=0
60y=18 /:60
y= 18/60=3/10
Answer: y = 1.3x + 1.8
Step-by-step explanation: I used Desmos
