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algol [13]
4 years ago
11

Does this equation represent a proportional relationship? y=x+1

Mathematics
2 answers:
kiruha [24]4 years ago
5 0
Yes it does represent a proportional relationship
Butoxors [25]4 years ago
3 0

Answer:

yes

Step-by-step explanation:

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5. A quarter is tossed in the air 300 times.
tankabanditka [31]

Answer:

C

Step-by-step explanation:

The probability of getting heads or tails is 50%.

300*50% = 150

3 0
3 years ago
Read 2 more answers
If (-3, y) lies on the graph of y = , then y =
ser-zykov [4K]

Answer:

The value of y is 64.

Step-by-step explanation:

The given equation is

y=(\frac{1}{4})^x

It is given that (-3, y) lies on the graph of y. It means the equation of the function must be satisfy by the point (-3,y).

Substitute x=-3 in the given equation to find the value of y,

y=(\frac{1}{4})^{-3}

y=4^{3}                      (\frac{a}{b})^{-n}=(\frac{b}{a})^n

y=64

Therefore the value of y is 64.

5 0
4 years ago
Which of the equation has a solution of 9.
Alla [95]
C has a solution of 9 you subtract 3 to get A=9
8 0
3 years ago
Read 2 more answers
The Turtle and Achilles compete. They start at the same time from the same place. Achilles runs at a speed of 13 mph while the T
grandymaker [24]

Answer:

2 minutes.  

Step-by-step explanation:

Let t be the time taken in competition and the distance covered by Achilles be x miles.

We have been given that when Achilles reaches the finish line, the Turtle is 2/5 of a mile behind him. This means that distance covered by turtle will be: x-\frac{2}{5}.

Achilles runs at a speed of 13 mph while the Turtle moves at a speed of 1 mph.

Since we know that \text{Time}=\frac{\text{Distance}}{\text{Speed}}, so we can set two equations for time taken by Achilles and turtle as:

t=\frac{x}{13}...(1)

t=\frac{(x-\frac{2}{5})}{1}...(2)

From equation (1) we will get,

x=13t

Upon substituting this value in equation (2) we will get,

t=\frac{13t-\frac{2}{5}}{1}    

Let us have a common denominator.  

t=\frac{\frac{65t-2}{5}}{1}

t=\frac{65t-2}{5}

Upon multiplying both sides of our equation by 5 we will get,

5t=5\times \frac{65t-2}{5}

5t=65t-2

5t-65t=65t-65t-2

-60t=-2

t=\frac{-2}{-60}

t=\frac{1}{30}

So, the competition took 1/30 hour, let us convert our given time in minutes.

\frac{1}{30}\text{ hour}\times \frac{60\text{ minutes}}{\text{hour}}

\frac{1}{30}\times 60\text{ minutes}

2\text{ minutes}  

Therefore, the competition took 2 minutes.


8 0
3 years ago
I need help with this plzzzz it's difficult?
belka [17]

Answer:

-2.5 (decimal) or -5/2 (fraction)

Step-by-step explanation:

5 0
3 years ago
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