Answer:
<u>C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g)</u>
The reaction consumes <u>2 moles of glucose </u>(C6H12O6). The reaction produces <u>12 moles of carbon dioxide</u> and <u>12 moles of water.</u>
<u />
Cl2(g) + 2NaI(aq) → 2NaCl(aq) + I2
(s)
The reaction consumes 3 moles of chlorine. The reaction produces 6 moles of sodium chloride and 3 moles of iodine.
3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(l)
The reaction consumes 2 moles of phosphoric acid. The reaction produces 2 moles of potassium phosphate and 6 moles of water.
Explanation:
When glucose (C6H12O6) reacts with oxygen, carbon dioxide and water are produced. The balanced equation for this reaction is:
<u>C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g)</u>
This means for 1 mol glucose we need 6 moles oxygen to produce 6 moles of CO2 and 6 moles H2O
If 12 moles of oxygen react, The reaction consumes <u>2 moles of glucose </u>(C6H12O6). The reaction produces <u>12 moles of carbon dioxide</u> and <u>12 moles of water.</u>
<u />
<u />
When chlorine reacts with sodium iodide, sodium chloride and iodine are produced. The balanced equation for this reaction is:
Cl2(g) + 2NaI(aq) → 2NaCl(aq) + I2
(s)
This means for 1 mol Cl2 we need 2 moles NaI to produce 2 moles NaCl and 1 mol I2
If 6 moles of sodium iodide react, The reaction consumes 3 moles of chlorine. The reaction produces 6 moles of sodium chloride and 3 moles of iodine.
When potassium hydroxide reacts with phosphoric acid, potassium phosphate and water are produced. The balanced equation for this reaction is:
3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(l)
This means for 3 moles KOH we need 1 mol H3PO4 to produce 1 mol K3PO4 and 3 moles H2O
If 6 moles of potassium hydroxide react, The reaction consumes 2 moles of phosphoric acid. The reaction produces 2 moles of potassium phosphate and 6 moles of water.