Answer:
The answer to your question is: 69.6 %
Explanation:
Freon -112 (C₂Cl₄F₂)
MW = (12 x 2) + (35.5 x 4) + (19 x 2)
= 24 + 142 + 38
= 204 g
204 g of C₂Cl₄F₂ ----------------- 100%
142 g ----------------- x
x = (142 x 100 ) / 204
x = 69.6 %
Moles of Ar = mass/atomic weight of Ar
= 22/39.948
= 0.55 moles
Hope this helps!
Answer:
6 Electrons r smaller than a proton or a neutron
Answer:
0.0928 grams of oxygen was collected.
Explanation:
Volume of oxygen gas collected = V= 75.3 mL = 0.0753 L (1 mL = 0.001 L)
Temperature of the gas = T = 25°C = 25+ 273 k = 298 K
Pressure of the gas = P - = 742 Torr - 24 Torr = 718 Torr
1 atm = 760 Torr
Moles of oxygen gas = n
Using an ideal gas equation;
n = 0.0029 mol
Mass of 0.0029 moles of oxygen gas :
0.0029 mol × 32 g/mol = 0.0928 g
0.0928 grams of oxygen was collected.