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IRISSAK [1]
3 years ago
5

In a mixture of hydrogen and nitrogen gases, the mole fraction of nitrogen is 0.333. If the partial pressure of hydrogen in the

mixture is 75.0 torr, what is the total pressure of the mixture
Chemistry
1 answer:
notka56 [123]3 years ago
4 0

Answer:

P_T=112.4torr

Explanation:

Hello there!

In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:

P_{H_2}=x_{H_2}*P_T

And can be solved for the total pressure as follows:

P_T=\frac{P_{H_2}}{x_{H_2}}

However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:

x_{H_2}+x_{N_2}=1\\\\x_{H_2}=1-0.333=0.667

Then, we can plug in to obtain the total pressure:

P_T=\frac{75.0torr}{0.667}\\\\P_T=112.4torr

Regards!

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Both diamond and graphite (i.e. pencil lead) consist of carbon atoms. They are only different in their crystalline structures. O
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Answer:

Moles of carbon atoms  = 3.33  ×  10^{-6} mol

No. of atoms of C in Diamond  = 2.007 ×   10^{28} atom

Atoms of graphite = 6.27 × 10^{23} Atoms

Explanation:

given data

Cost of 0.2g of diamond = $5000

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solution

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and Moles of carbon atoms  is express as

Moles of carbon atoms = Given mass of Carbon ÷ atomic mass of C      .........1

Moles of carbon atoms  = 4.0  ×  10^{-5}    g/ 2.0g

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and

No. of atoms of C in Diamond = No. of moles × Avogadro NO    ..............2

No. of atoms of C in Diamond  = 3.33 ×   10^{-6} mol × 6.022 ×   10^{28}

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Graphite

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6 0
3 years ago
A chemist has 3.55x1022 molecules of nitrogen monoxide. How
Alina [70]

Answer:

<h2>0.059 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

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From the question we have

n =  \frac{3.55 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.05897...

We have the final answer as

<h3>0.059 moles</h3>

Hope this helps you

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