Ok so what you have to do is multiply all the numbers ! Hope this helps so the answer is 127 !
Answer:
2: option four
3: option four
Step-by-step explanation:
they are both option four
The smallest of the three consecutive integers is 24.
<h3>How to solve algebraic word problems?</h3>
Let the 3 consecutive integers be;
x, y and z
Thus;
y = x + 1
z = x + 2
Now, we are told that their sum is equal to 4 times the largest number minus 29. Thus;
x + x + 1 + x + 2 = 4(x + 2) - 29
3x + 3 = 4x + 8 - 29
4x - 3x = 3 + 21
x = 24
Thus, we can conclude that the smallest of the three consecutive integers is 24.
Read more about algebra word problems at; brainly.com/question/13818690
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Answer:
8x + 7y = 30 ( one solution)
8x - 7y = 2
-8x + 7y = -2 ( infinitely many solutions )
8x - 7y = 2
8x - 7y = 2
-8x + 7y = 2 ( zero solutions )
Answer:
4.
Step-by-step explanation:
You are so smart. 5 - (-7) = 5+7 which = 12. 12/3 is 4.
