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Galina-37 [17]
3 years ago
5

50 POINTS !! PLEASE HELP ILL GIVE BRAINLIEST !!

Mathematics
2 answers:
dolphi86 [110]3 years ago
7 0

Answer:

The answer to your question is 3

Step-by-step explanation:

Colt1911 [192]3 years ago
6 0

Answer:

Step-by-step explanation:

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Probability of drawing a face card or 4 is 16/52=4/13
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Name the slope perpendicular to 3/4.
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The perpendicular slope is -4/3

Step-by-step explanation:

Perpendicular slopes multiply to -1

m * 3/4 = -1

Multiply each side by 4/3

m * 3/4 *4/3 = -1 * 4/3

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The perpendicular slope is -4/3

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Graph the equation y = -3x on a graph
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Put a dot on the -3 from the y-axis and draw a straight line from left to right.

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3n+22 +2n+38=180 m angle
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3 years ago
A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he
Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

 n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0
3 years ago
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