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Nookie1986 [14]
3 years ago
5

What are the aptitude, period, and midline of the function?

Mathematics
1 answer:
tester [92]3 years ago
6 0
The picture won’t show on mine?
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Dhaulagiri is the 7th highest mountain in the world. Ms. Fink is walking through
11111nata11111 [884]

Answer:

4833 m

Step-by-step explanation:

Given that her angle of elevation at the first recording is 47.3 at an altitude of 4900 m

We use Pythagoras Theorem to get this done

We can say that the opposite of the angle is the altitude, while the hypotenuse of the triangle, is the distance between herself and the top

Using the sine angle rule, we have

Sine 47.3 = 4900 / h

h = 4900 / sin 47.3

h = 4900 / 0.7349

h = 6668 m

This means that she was 6668 m away from the top of the mountain

She then moves 1000 m closer to the mountain top, this means that our h = 6668 - 1000

Using the same sine angle rule, we have

Sine 58.5 = o / 5668

o = 5668 * sine 58.5

o = 5668 * 0.8526

o = 4833 m

She is 4833 m above the sea level

5 0
3 years ago
Who can tutor me for free
krok68 [10]

Answer:

Do not ask for free tutoring (Nobody will really do it)

Step-by-step explanation:

Just use Brainly! Ask for questions and explanations and do what you can to get your work done. After that if you need further help then ask a parent/guardian/sibling or someone you know for help and if that doesn't work then come back to this. Hope this helps.

4 0
2 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
How do I solve 12 + 2x + 1 = 59
aksik [14]
You can look up cymath.com it will work the problem out for you and show you the steps.
3 0
3 years ago
Read 2 more answers
Please help will give branliest! Find the two missing sides and write your answer as in simplified radical form.
hjlf

Answer: v = u= 2 \sqrt{2}

Step-by-step explanation:

v= cos45 * 4= 2 \sqrt{2}

- Apply Pythagorean theorem

4^{2}= (2\sqrt{2}) ^{2} + u^{2}

We have u = 2 \sqrt{2}

5 0
3 years ago
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