The answer to this question is 25,686
I am not sure is you are supposed to solve or rewrite but for solving its this picture, tell me if its rewriting the problem and ill give you that as well!
Answer:
The formula for this quadratic function is x*2 +6x+13
Step-by-step explanation:
If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this
y= a (x-h)*2 + K
Quadratic function looks like this
y= ax*2 + bx + c
So let's find the a
y= a (x-h)*2 + K where
y is 13, x is 0, h is -3 and K is 4
13= a (0-(-3))*2 +4
13=9a +4
9=9a
9/9=a
1=a
The quadratic function will be
y= 1(x+3)*2 + 4
Let's get the classic form
(x+3)*2 = (x+3)(x+3)
(x*2+3x+3x+9)
x*2 +6x+13
f(0) = 13
Answer:
LAST OPTION: 
Step-by-step explanation:
For this exercise it is important to remember the Power of a power property, which states that:

The expression given in the exercise is:

Therefore, in order to simplify it, you must apply the Power of a power property explained before.
Then, you get the following expression:

As you can notice, the expression obtained matches with the expression provided in the last option.