I am not sure is you are supposed to solve or rewrite but for solving its this picture, tell me if its rewriting the problem and ill give you that as well!

3 0

2 years ago

Write the standard form of the quadratic function whose graph is a parabola with the given vertex and that passes through the gi

maks197457 [2]

Answer:

The formula for this quadratic function is x*2 +6x+13

Step-by-step explanation:

If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this

y= a (x-h)*2 + K

Quadratic function looks like this

y= ax*2 + bx + c

So let's find the a

y= a (x-h)*2 + K where

y is 13, x is 0, h is -3 and K is 4

13= a (0-(-3))*2 +4

13=9a +4

9=9a

9/9=a

1=a

The quadratic function will be

y= 1(x+3)*2 + 4

Let's get the classic form

(x+3)*2 = (x+3)(x+3)

(x*2+3x+3x+9)

x*2 +6x+13

f(0) = 13

6 0

4 years ago

Read 2 more answers

Simplify the expression.

Sati [7]

Answer:

LAST OPTION: $x^9$

Step-by-step explanation:

For this exercise it is important to remember the Power of a power property, which states that:

$(a^m)^n=a^{mn}$

The expression given in the exercise is:

$(x^\frac{3}{2})^6$

Therefore, in order to simplify it, you must apply the Power of a power property explained before.

Then, you get the following expression:

$=x^{(\frac{3}{2}*6)}=x^{(\frac{3*6}{2})}=x^{\frac{18}{2}}=x^9$

As you can notice, the expression obtained matches with the expression provided in the last option.

6 0

3 years ago

Given the arithmetic series: 2+4+6+... find the sum of T41 to T47.​

Given the arithmetic series: 2+4+6+... find the sum of T41 to T47.