a)
Kinetic energy (KE) = 1/2 m v^2
Where:
m = mass = 1260 kg
v = speed = 66.3 km/h = 18.42 m/s
Replacing:
KE = 1/2 (1260 kg ) (18.42 m/s )^2 = 213,756.7 J
Here are some examples of field force:
1. <span>1) electrostatic force of attraction or repulsion on a charged particle in an electric field
2. </span><span>) magnetic force on charged particles moving at right angles with a magnetic field. Magnetic force also affects magnetic poles.
I hope this helps. </span>
Answer:
Pure research is conducted without any specific goal in mind. Applied research is conducted in order to solve a specific and practical problem, unlike pure research. Hope this helped.
As the temperature of the lead and helium is the same. Thus the average kinetic energy is also the same for lead and helium.
Reason:
It is given that a 5.0-kg bar of lead is placed inside a 12-L chamber filled with helium gas. The temperature of the lead and helium is the same. It is required to compare the average kinetic energy of the lead atoms and helium atoms.
The average kinetic energy is calculated as,
.
Here K is the average kinetic energy, R is the gas constant, N is the Avogadro's number, and T is the temperature.
As the temperature is the same for both lead and helium. As a result, the average kinetic energy is also the same for lead and helium.
Learn more about average kinetic energy here,
brainly.com/question/1599923
#SPJ4