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3 years ago

Who were Socrates and Plato

Physics

2 answers:

VARVARA [1.3K]3 years ago

8 0

Socrates was a classical Greek philosopher and Plato was a philosopher in Classical Greece

Sophie [7]3 years ago

6 0

Greek philosopher and love asking many different questions for his teaching style.

Plato was a greek philosopher and student of Socrates. He believed that an ideal society would be run by people who were philosophers.

You might be interested in

Why are the alkali metals likely to react with group 17 elements?

Rudiy27

Answer:

Because alkali metals are so reactive, they are found in nature only in combination with other elements. They often combine with group 17 elements, which are very “eager” to gain an electron.

Explanation:

hope this helps you if it does please mark brainliest

7 0

2 years ago

A passenger on a stopped bus notices that rain is falling vertically just outside the window. When the bus moves with constant v

nekit [7.7K]

Answer:

1)0.325

2) $6.17\ \rm m/s$

Explanation:

<u>Given:</u>

The angle that falling raindrops make with the vertical= $18^\circ$

Let $V_R$ be the velocity of the raindrops and $V_B$ be the velocity of the bus.

$\dfrac{V_R}{V_B}=\tan 18^\circ\\\dfrac{V_R}{V_B}=0.315\\$

2)Speed of the raindrops $=0.315\times 19$

$=6.17\ \rm m/s$

5 0

2 years ago

For this triangle...?

Mariulka [41]

<h3><u>Answer</u>;</h3>

= 0.6

<h3><u>Explanation</u>;</h3>

Using Pythagoras theorrem

Base² + height ² = Hypotenuse²

Thus;

Base² = 15² - 12²

= 81

Base = √81 = 9

But; cosine = adjacent/hypotenuse

Hence; cos θ = 9/15

5 0

3 years ago

Read 2 more answers

A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.

Kobotan [32]

Explanation:

The given data is as follows.

F = $5.75 \times 10^{-16} N$

q = $1.6 \times 10^{-19} C$

v = 385 m/s

$sin (63.9^{o})$ = 0.876

Now, we will calculate the magnitude of magnetic field as follows.

B = $\frac{F}{qv sin (\theta)}$

= $\frac{5.75 \times 10^{-16} N}{1.6 \times 10^{-19} C \times 385 m/s \times 0.876}$

= $0.01065 \times 10^{3}$ T

= 10.65 T

Thus, we can conclude that magnitude of the magnetic field is 10.65 T.

4 0

3 years ago

If a 10kg block is at rest on a table and a 1200N force is applied in the eastward direction for 10 seconds, what is the acceler

gavmur [86]

Answer:

a = 120 m/s²

Explanation:

We apply Newton's second law in the x direction:

∑Fₓ = m*a Formula (1)

Known data

Where:

∑Fₓ: Algebraic sum of forces in the x direction

F: Force in Newtons (N)

m: mass (kg)

a: acceleration of the block (m/s²)

F = 1200N

m = 10 kg

Problem development

We replace the known data in formula (1)

1200 = 10*a

a = 1200/10

a = 120 m/s²

6 0

3 years ago