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ExtremeBDS [4]
2 years ago
11

Suppose you are in total equilibrium in water (in other words you are floating and not moving in any direction)What could you do

to move yourself up? Down? Forward? Backward? Left? Right? Why does this work?
Physics
1 answer:
Eva8 [605]2 years ago
5 0

Explanation:

According to newtons first law of motion:

'' a body will continue in its state of rest or uniform motion along a path unless it is acted upon by an external force".

A body in equilibrium that is floating will be stable and not move in any direction. Even if it moves, the motion will be constant wouldn't change.

  • To move the body in any direction, one has to swim.
  • Swimming is the application of an external force to counter the balanced forces at equilibrium on a body.
  • This works when the net external force is greater than that the balanced forces.

learn more:

Newton brainly.com/question/11411375

#learnwithBrainly

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I wonder if people that say that there ugly is to get attention (not to be mean...)​
alexandr1967 [171]
They do. mostly because they want validation from others
5 0
2 years ago
Read 2 more answers
Imagine you can take all the atoms in a single drop of water and put them on a single line as closely packed as they can be. How
tester [92]

Answer:

option a

Explanation:

Size of an atom (diameter) = 10⁻¹⁰ m

There are approximately 10²² atoms in a single drop of water. If they are put in  a straight line, the length would be

l = diameter of an atom × number of atoms

l = 10²²×  10⁻¹⁰ m = 10¹² m

Distance between the Sun and the Earth is 1.47 × 10¹¹ m. The calculated length is greater than the distance between the Sun and the Earth.

Thus, option a is correct.

7 0
3 years ago
An object, experiencing no friction, keeps moving at a constant speed. What can we say about the net force on the object?
sleet_krkn [62]

Answer:

Explanation:

Let's look at a mathematical representation of this. The equation for tis is just a souped up version of Newton's 2nd Law:

F - f = ma. It an object is moving at a constant speed, the acceleration of that object is 0. That changes this equation to

F = f which states that the applied Force equals the frictional force, choice a.

3 0
2 years ago
On a vacation flight, you look out the window of the jet and wonder about the forces exerted on the window. Suppose the air outs
user100 [1]

Answer:

A) \Delta P =  14512.5 Pa = 14.512 kPa

B) F = 1632.65 N

Explanation:

Given details

outside air speed is given as v_2 = 150 m/s

since inside air is atmospheric , v_1 = 0 m/s

a) By using bernoulli equation between outside and inside of flight

P_1 + \frac{1}{2} \rho v_1^2 + \rho gh = P_2 + \frac{1}{2} \rho v_2^2 + \rho gh

\Delta P = \frac{1}{2} \rho v_2^2 - \frac{1}{2} \rho v_1^2

\Delta P = \frac{1}{2} \rho[ v_2^2 -v_1^2]

\Delta P = \frac{1}{2} 1.29 [ 150^2 - 0^2]

\Delta P =  14512.5 Pa = 14.512 kPa

b) force exerted on window

Area of window  = 25\times 45 = 1125 cm^2 = 0.1125 m^2

We know that force is given as

F = P\times A

F = 14512.5 \times 0.1125

F = 1632.65 N

5 0
3 years ago
If the plane is flying in a horizontal path at an altitude of 98.0 m above the ground and with a speed of 73.0 m/s, at what hori
snow_lady [41]

Explanation:

The given data is as follows.

     height (h) = 98.0 m,     speed (v) = 73.0 m/s,

Formula of height in vertical direction is as follows.

          h = \frac{gt^{2}}{2},

or,      t = \sqrt{\frac{2h}{g}}

Now, formula for the required distance (d) is as follows.

       d = vt

          = v \sqrt{\frac{2h}{g}}  

        = 73.0 m/s \sqrt{\frac{2 \times 98.0 m}{9.8 m/s^{2}}}  

          = 326.5 m

Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.

8 0
3 years ago
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