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ExtremeBDS [4]
3 years ago
11

Suppose you are in total equilibrium in water (in other words you are floating and not moving in any direction)What could you do

to move yourself up? Down? Forward? Backward? Left? Right? Why does this work?
Physics
1 answer:
Eva8 [605]3 years ago
5 0

Explanation:

According to newtons first law of motion:

'' a body will continue in its state of rest or uniform motion along a path unless it is acted upon by an external force".

A body in equilibrium that is floating will be stable and not move in any direction. Even if it moves, the motion will be constant wouldn't change.

  • To move the body in any direction, one has to swim.
  • Swimming is the application of an external force to counter the balanced forces at equilibrium on a body.
  • This works when the net external force is greater than that the balanced forces.

learn more:

Newton brainly.com/question/11411375

#learnwithBrainly

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A thin oil slick (no=1.50) floats on water (nw=1.33). When a beam of white light strikes this film at normal incidence from air,
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Answer:

The (minimum) thickness of the oil slick is 325 nm.

Explanation:

Let the (minimum) thickness of the oil slick = t_{o}

Therefore:

2t_{o} = (m_{red}+\frac{1}{2})*λ_{red}/n_{o}       (1)

similarly,

2t_{o}=(m_{violet}+\frac{1}{2})*λ_{violet}/n_{o}                                (2)

Thus, equation 1 = equation 2

(m_{red}+\frac{1}{2})*λ_{red} /n_{o} = (m_{violet}+\frac{1}{2})*λ_{violet}/n_{o}

Where:

λ_{red} = 650 nm

λ_{violet} = 390 nm

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Therefore:

\frac{2m_{violet}+1 }{2n_{red}+1 }=650/390=5/3

This shows that,

m_{violet}=2

m_{red}=1

Thus, using equation 2

t_{o}=\frac{5*390}{2*2*1.5} =325 nm

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