<u>Answer:</u>
When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules
<u>Solution:</u>
We know 
Anne is pushing the wheelbarrow with a force of 70 N at an angle of
with the horizontal
So the force of Anne will be 
She pushes the wheelbarrow 25 meter, So D = 25 meters
So, the 
Anne has done total 1120 joules work.
Answer:
Solution : Third Option
Step-by-step explanation:
The first step here is to make all the signs uniform. As you can see the third inequality has a less than sign, which we can change to a greater than sign by dividing negative one on either side, making the inequality y > - 7.

Now take a look at the third option. Of course the y - coordinate, 3, is greater than - 7, so it meets the third requirement ( y > - 7 ). At the same time 3 > 1( 2 ) > 2, and hence it meets the second requirement as well. 3 > - 3( 1 ) + 4 > - 3 + 4 > 1, meeting the first requirement.
Therefore, the third option is a solution to the system.
Y-3=5(x-2)
y-3=5x-10
y=5x-13
the slope is 5