All categories

2 years ago

Help me please please help please

Mathematics

2 answers:

Dominik [7]2 years ago

7 0

Answer:

Step-by-step explanation:

180-81 = 99

Hope this helps!

Mila [183]2 years ago

5 0

Anwser: B

Step-by-step explanation:

*Both angle 3 & 4 make a linear angle

*A linear angle equals to 180 degrees

1) 180 -81 = 99 degrees

The anwser is B, hoped that helped ;)

You might be interested in

Find the absolute value of 1 and - 1

AlekseyPX

The absolute value of BOTH of those numbers is ' 1 '.

==========================================

Oh ! Wait just a second. Did you mean for the 1 and the -1 to be combined
in some way ? If that's what you had in mind, then you'll have to be more
specific. "And" is no mathematical operation that I know of.

5 0

3 years ago

Read 2 more answers

Help math beats me up in dark alleys

andriy [413]

Replace x with 3:

f(x) = 20(0.5)^x

f(3) = 20(0.5)^3

First do 0.5^3 = 0.125

Now multiply that by 20:

20 x 0.125 = 2.5

f(3) = 2.5

3 0

2 years ago

One side of a square is 4x, what is the area of this square?

Degger [83]

Answer:

16x^2

Step-by-step explanation:

To find the area of a square, we use the formula

A = s^2 where s is the side length

A = (4x)^2

A = 16x^2

3 0

2 years ago

Read 2 more answers

Need help on this question please!

podryga [215]

Answer:

The answer is -46

6 0

2 years ago

A geometric sequence has first term 1/9 and common ratio 3. Which is the first term of the sequence which exceeds 1000?

Svetach [21]

$a_{n}= \frac{1}{9} (3)^{n-1}$
(We know this from a=1/9 and r=3)
Simplifying this, we get:
$\frac{1}{9} (3)^{-1} (3)^n$

Since we're finding the first term that exceeds 1000, let's set it equal to 1000.

$\frac{1}{27}(3)^n=1000$
Multiplying both sides by 27
$3^n=27000$

$log_{3}27000=n$

n≈9.2

We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
$\frac{1}{27}3^{10}$
=2187

Therefore the first term that exceeds 1000 is 2187, and it is the 10th term

3 0

2 years ago