Question

Give the percent yield when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2. (20 points)
2C8H18 + 25O2 → 16CO2 + 18H2O

Answer 1

Percent yield is 23.11 % when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2.

Explanation:

Balanced equation for the chemical reaction:

2C8H18 + 25O2 → 16CO2 + 18H2O

data given:

CO2 formed (actual yield)  = 162.8 grams

mass of oxygen = 218 grams

16 moles of CO2 formed when 5 moles of oxygen reacted

3.6 moles of CO2 formed when 6.8 moles of oxygen reacted.

In the reaction 16 moles of CO2 will have 44.01 x 16

                                      theoretical yield of CO2    = 704.16 grams

percent yield = $\frac{actual yield}{theoritical yield}$   x100

         putting the values in the above equation

percent yield = $\frac{162.8}{704.16}$  x 100

                       = 0.23 x 100

                           = 23.11 %

Percent yield is 23.11 %.