Boron has two isotopes, Boron 10 which has a mass of 10.0129 amu and Boron-11 with a mass of 11.0093 amu. B-10 occurs 84.74% of
1 answer:
The average atomic mass of Boron: 10.431 amu
<h3>Further explanation </h3>Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.
So Isotopes are elements that have the same Atomic Number (Proton)
Atomic mass is the average atomic mass of all its isotopes
In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu
Mass atom X = mass isotope 1 . % + mass isotope 2.% + ...
The average atomic mass of boron :
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The electron configuration of V³⁺ is [Ar]. The ion is paramagnetic because it has two unpaired electrons
- A weak magnetic field supplied externally can weakly attract some materials, which then create internal magnetic fields that are directed in the same direction as the applied magnetic field. This phenomenon is known as paramagnetic.
- Diamagnetic materials, in contrast, are attracted to magnetic fields and produce induced magnetic fields that are directed in the opposite direction from the applied magnetic field.
- The majority of chemical elements and some compounds are considered to be paramagnetic materials.
- Paramagnetic materials have a relative magnetic permeability that is somewhat more than 1, which makes them attracted to magnetic fields.
- The applied field induces a linearly decreasing magnetic moment that is relatively weak.
- Modern experiments on paramagnetic materials are frequently done with a sensitive analytical balance since it typically requires a sensitive analytical balance to identify the effect.
To learn more about paramagnetic with the given link
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Answer:
Explanation:
Hello there!
In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:
Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:
Therefore, the partial pressure of chloroform turns out to be:
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