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KiRa [710]
3 years ago
11

What is the relationship between the 1s in 911,147,835

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0
I'm not completely sure what you're asking, but if i understand right, it could be that if you add 5 and 3 you get 8, or if you subtract 3 from 8 you get 5.

Hope this helps in some way!
eimsori [14]3 years ago
3 0
Is this is was you mean:
The one in (91)1 is 10 times the one in 91(1). Same with the one is 147.
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aleksandr82 [10.1K]

Answer:

1.) 1/4

2.) 5/12 i am not sure about this one

Step-by-step explanation:

1.) Chance of tales:

Chance of even number: 3/6 or 1/2

Multiply: (1/2)(1/2) = 1/4

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2 years ago
Given the formula A = pi r squared, how does the A vary in relation to the square of the radius?
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D

Step-by-step explanation:

Abosluelt no relationship.

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5 0
3 years ago
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Step-by-step explanation:

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3 years ago
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
ra1l [238]

Answer:

The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

For a 90% confidence the level of significance is  \alpha  = [100 - 90]\% =  0.10 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

So we see with decreasing confidence level the critical value  decrease

Now the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

         E\ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Hence for  reducing confidence level the margin of error will be reducing

  The  confidence interval is mathematically represented as

        \= x  - E  <  \mu <  \= x  + E

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value  reduces, the margin of error  reduces and the confidence interval becomes narrower

3 0
3 years ago
A picture measuring 2.5 inch high by 6 in wide is to be enlarged so that the width is now 18 in how tall will the picture be
lutik1710 [3]
The picture will now be 7.5 inches high by 18 inches wide.
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