Using f(X)=x+2 and g(x)=10x-4 , what is f(2) + g(4) ?

Mathematics

1 answer:

Ksivusya [100]3 years ago

3 0

F(2)+g(4)
evaluate them seperately
f(2)=2+2=4

g(4)=10(4)-4
g(4)=40-4
g(4)=36

f(2)+g(4)=4+36=40

You might be interested in

(sqrt(6))/(8+\sqrt(10))

valkas [14]

Answer:

$\frac{4\sqrt{6}-\sqrt{15}}{27}$

Step-by-step explanation:

$\frac{\sqrt{6} }{8+\sqrt{10} } \\\\\mathrm{Multiply\:by\:the\:conjugate}\:\frac{8-\sqrt{10}}{8-\sqrt{10}}\\=\frac{\sqrt{6}\left(8-\sqrt{10}\right)}{\left(8+\sqrt{10}\right)\left(8-\sqrt{10}\right)}\\\\\sqrt{6}\left(8-\sqrt{10}\right)=8\sqrt{6}-2\sqrt{15}\\\left(8+\sqrt{10}\right)\left(8-\sqrt{10}\right)=54\\\\=\frac{8\sqrt{6}-2\sqrt{15}}{54}\\\\\mathrm{Factor}\:8\sqrt{6}-2\sqrt{15}:\quad 2\left(4\sqrt{6}-\sqrt{15}\right)\\\\=\frac{2\left(4\sqrt{6}-\sqrt{15}\right)}{54}\\$

$\mathrm{Cancel\:the\:common\:factor:}\:2\\\\=\frac{4\sqrt{6}-\sqrt{15}}{27}$

5 0

3 years ago

A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$