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Colt1911 [192]
3 years ago
9

Using f(X)=x+2 and g(x)=10x-4 , what is f(2) + g(4) ?

Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0
F(2)+g(4)
evaluate them seperately
f(2)=2+2=4

g(4)=10(4)-4
g(4)=40-4
g(4)=36

f(2)+g(4)=4+36=40
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Annie have 56 stamps that are 26 less than one half of my stamps how many stamps do i have?​
Ksivusya [100]

Answer:

<em>You have 164 stamps.</em>

Step-by-step explanation:

Let the no. of my stamps be 'x'

Half of x subtracted by 26 = 56

\frac{1}{2} x - 26 = 56

\frac{1}{2} x = 56 + 26 =  82

x = 82 x 2 =  164

Let's check

\frac{164}{2} - 26 = 56

\frac{164}{2} = 56 + 26

164     = 82 x 2

164 = 164!

The answer is correct.

6 0
2 years ago
PLEASE HELP ME ON THIS PLZZZZZ!!!!!
Bogdan [553]

Answer:

-2,-9

Step-by-step explanation:

im not 100 perent sure ifthis is right or not

6 0
3 years ago
Read 2 more answers
A circle with circumference 6 has an arc with a 20º central angle.
Ray Of Light [21]

Answer:

length of an arc =1 /3 unit or 0.3unit

Step-by-step explanation:

to calculate the length of an arc, having it in mind that the arc is a portion of the circumference of a circle.

circumference of a circle = 6unit

Ф = 20°

recall,

the formulae for finding the length of an arc

= 2πr(Ф/360)

assuming that r is the radius of the circle

so, the circumference of a circle is given to be = 2πr

6 = 2πr

r = (6/2π)

length of an arc = 2πr(Ф/360)

remember that r = (6/2π)

length of an arc = 2π(6/2π) [20°/360°]

length of an arc =  6 × 20°/360°

length of an arc = 120°/360°

length of an arc = 1/3unit

4 0
3 years ago
Write an equation of the line that passes through the given point P and
dexar [7]

Answer <u>(assuming it can be in point-slope form)</u>:

y-4 = 3(x+2)  

Step-by-step explanation:

Use the point-slope formula y-y_1 = m (x-x_1), to write the equation of the line in point-slope form. Substitute x and y values for m, x_1, and y_1 in the formula.

Since m represents the slope, substitute 3 for it. Since x_1 and y_1 represent the x and y values of a point the line intersects, take the x and y values of point P and substitute them into the equation as well. Substitute -2 for x_1 and 4 for y_1. This gives the following answer:

y-4 = 3(x+2)

5 0
3 years ago
The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence
disa [49]

Answer:

95% confidence interval for the mean weight of newborn elephant calves is between a lower limit of 240.87 pounds and an upper limit of 247.13 pounds.

Step-by-step explanation:

Confidence Interval = mean + or - Error margin (E)

mean = 244 pounds

sd = 11 pounds

n = 50

degree of freedom = n - 1 = 50 - 1 = 49

Confidence level = 95%

t-value corresponding to 49 degrees of freedom and 95% confidence level is 2.010

E = t×sd/√n = 2.010×11/√50 = 3.13 pounds

Lower limit = mean - E = 244 - 3.13 = 240.87 pounds

Upper limit = mean + E = 244 + 3.13 = 247.13 pounds

95% confidence interval is between 240.87 and 247.13 pounds.

5 0
3 years ago
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