-33,600. To get this you multiply -4,200 by 8
Answer:
21
Step-by-step explanation:
The answer is 21 because for finding the area you have to multiply, 7 and 3.
Multiply 7 and 3 you get 21.
Hope this helps :)
Answer:

Step-by-step explanation:
Given
Geometry Progression


Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP

For first term: Tn = 500 and n = 1




For fought term: Tn = 32 and n = 4


Substitute 500 for a

Make r^3 the subject


Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)

Using: 
and 




<em>Hence, the second term is 200</em>
The answer to this question would be: 85/99
In this question, Suzan is taking 8 marble from a bag containing 4 red marbles, 4 green ones, 2 white ones, and 2 purple ones. The total marble in the bag should be: 4+4+2+2= 12. The question is how much the probability to get <4 red marble. In this question, the green, white and purple is not specified so you can join them into not red group. It will be easier to find the probability of "have all the red one" which mean Suzan take 4 red marble and 4 not-red marble<span>
Ways to take 8 marble out of 12=12C5= 12!/4!8!= </span>495
Ways to take 4 red marble out of 4= 4C4= 1
Ways to take 4 not red marble out of 8= 8C4= 8!/4!4!= 70
Probability to <span>have all the red ones= 1*70/495= 14/99
</span>Then the probability does not have all the red ones= 99/99 - 14/99= 85/99
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>