3 years ago

Find the simple interest paid one $600 is borrowed for three years at 6% per

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

Principal amount= $600

Time= 3 years

Rate of Interest = 6%

SI= PRT/100

= 600x6x3/100

= $108

Interest is $108

Step-by-step explanation:

You might be interested in

What is 8+9 pllllllllllllssssssssssssssssssssssssss

KiRa [710]

Answer:

Step-by-step explanation:

8+9 is 17

5 0

2 years ago

Read 2 more answers

What is 3,567,194 rounded

coldgirl [10]

4,000,000 is 3,567,194 rounded (-:

4 0

2 years ago

If Jorge has 61 hours of work to do and he can work 7.5 hours a week, how many days will it take for him to finish it all.

mestny [16]

Answer:57 days

Step-by-step explanation:

3 0

3 years ago

Two gallons of gasoline cost $7.96, 5 gallons cost $19.90, and 12 gallons cost $47.76. Which equation gives the total cost y of

Nikolay [14]

Answer:

9.7921

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec

elena-14-01-66 [18.8K]

If $S(t)$ is the amount of strontium-90 present in the area in year $t$ , and it decays at a rate of 2.5% per year, then

$S(t+1)=(1-0.025)S(t)=0.975S(t)$

Let $S(0)=s$ be the starting amount immediately after the nuclear reactor explodes. Then

$S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)$

or simply

$S(t)=0.975^ts$

So that after 50 years, the amount of strontium-90 that remains is approximately

$S(50)=0.975^{50}s\approx0.282s$

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

$S(t)=se^{kt}$

where $t$ is measured in years. We're told that 2.5% of the starting amount $s$ decays after 1 year, so that

$0.975s=se^k\implies k=\ln0.975$

Then after 50 years, we have

$S(50)=se^{50k}\approx0.282s$

5 0

2 years ago