Quite tricky but my answer would be D
Hello! To draw a triangle, first, we have to follow a condition of existence.
This rule is:
• one of the sides must be ,bigger, ,than the absolute value, of the ,difference between the other two, sides
• the unknown side must be ,smaller ,than the ,sum of the other, two sides.
Let's write these rules using a, b, and c for the sides:
Considering a = 7.8 and b = 5.6:
[tex]\begin{gathered} |a-b|So, the
third side must be
smaller than 13.4 and bigger than 2.2.
Answer:
Step-by-step explanation:
<u>Given triangle ACD</u>
- AB = BC
- CD = 2x + 6
- AB = x + 5
- BC = 2x - 3
- P = ?
<u>Perimeter is sum of the side lengths:</u>
AD = CD because D is vertex and the triangle is isosceles
AC = AB + BC because B is midpoint of AC
<u>Then P is:</u>
- P = 2(2x + 6) + (x + 5) + (2x -3) = 4x + 12 + x + 5 + 2x - 3 = 7x + 14
<u>Find the value of x from the AB = BC:</u>
- x + 5 = 2x - 3
- 2x - x = 5 + 3
- x = 8
<u>Then find the value of P:</u>
- P = 7*8 + 14 = 56 + 14 = 70 units
The probability of three independent events happening one after the other is the multiplication of the probability of the single events.
The probability of spinning an odd number is 5/10=1/2, because there are 5 odd numbers (1,3,5,7 and 9) out of the 10 numbers from 1 to 10.
The probability of spinning a number less than 4 is 3/10, because there are 3 numbers (1,2 and 3) that are less than 4 out of the 10 numbers from 1 to 10.
The probability of spinning a 7 is 1/10, because you only have one good outcome out of 10.
So, the probability of winning the game is
