Let's make,
mechanic #1's rate = x
mechanic #2's rate = y
* Their rate is dollars per hour ($/hr)
mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1
and mechanic #2 worked for 5 hours
5y = money earned by mech#2
together they charged a total of $1150. So the amount of money earned by both mechanics.
20x + 5y = 1150
the sum of the two rates was $95 per hour.
x + y = 95
which means
x = 95 - y
plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.
20(95 - y) + 5y = 1150
solve for y
1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr
Now use this to solve for x
x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr
mech#1 charged 45$/hr
mech #2 charged 50$/hr
What I got was 9/10 or you could make it into a percentage 90% hope this helps
Answer:
Step-by-step explanation:
b(a + 1) + a = b*a + b + a = ab + b + a
1) b(2a +1 ) = b*2a + b*1 = 2ab + b Not equivalent.
2)a + (a +1)*b = a + ab+ b Equivalent
3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a Not equivalent.
4) (a + 1)b + a = ab+ b + a Equivalent
5) a + b(a+1) = a +ab + b Equivalent
6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b Not equivalent.
7) a(b +1) + b = ab + a + b Equivalent
