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3 years ago

8

Lol I need help with this one too

1 answer:

dsp733 years ago

3 0

Answer: 7.3

Step-by-step explanation:

The square root of 53 is 7.28010988928, and if you round that number to the nearest tenth it is 7.3.

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..the cat and the hat to the pat in the rug on the hug

swat32

Answer:

uh get it i guess?

Step-by-step explanation:

yes

8 0

2 years ago

What is the slope-intercept form of the linear equation 2x–8y=32?

skelet666 [1.2K]

Answer: y = 1/4x - 4

Step-by-step explanation: write it in slope intercept form y = mx + b

3 0

3 years ago

LOTS OF POINTS <br> Simplify the expression by factoring, showing the steps in your work

julia-pushkina [17]

Answer:

$\frac{3x+7}{4x+1}$

Step-by-step explanation:

$\frac{12x^2+31x+7}{16x^2+8x+1}$

First you factor $12x^2+31x+7$ :

$=\left(12x^2+3x\right)+\left(28x+7\right)$

Then you factor out $3x$ from $12x^2+3x$ :

$12x^2+3x$

$=12xx+3x$

$=3\cdot \:4xx+3x$

$=3x\left(4x+1\right)$

Then you factor out 7 from $28x+7$ :

$28x+7$

$=7\cdot \:4x+7$

$=7\left(4x+1\right)$

$=3x\left(4x+1\right)+7\left(4x+1\right)$

Factor out common term $4x+1$ :

$=\left(4x+1\right)\left(3x+7\right)$

$\frac{\left(4x+1\right)\left(3x+7\right)}{16x^2+8x+1}$

Factor $16x^2+8x+1$ :

$=4^2x^2+8x+1$

$=4^2x^2+8x+1^2$

$=\left(4x\right)^2+8x+1^2$

$=\left(4x\right)^2+2\cdot \:4x\cdot \:1+1^2$

Use the perfect square formula:

$=\left(4x+1\right)^2$

$\frac{\left(4x+1\right)\left(3x+7\right)}{\left(4x+1\right)^2}$

Cancel out common factor $4x+1$ :

$=\frac{3x+7}{4x+1}$

8 0

3 years ago

In an arithmetic sequence {an}, if a1 = 5 and d = 3, find a72. A) 216 B) 218 C) 221 D) 223

Phoenix [80]

The arithmetic sequence with the given condition is determined recursively by

$\begin{cases}a_1=5\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}$

So we have

$a_2=a_1+3$

$a_3=a_2+3=a_1+3(2)$

$a_4=a_3+3=a_1+3(3)$

and so on with the general pattern

$a_n=a_1+3(n-1)$

This means the 72nd term in the sequence is

$a_{72}=a_1+3(72-1)=5+3(71)=218$

so the answer is B.

6 0

3 years ago

Steven conjectures that for |x|>5, it is true that x^3>125. Is his conjecture correct? Why or why not?

vredina [299]

Conjectures are conclusions formed from evidences. Steven's conjecture that: $x^3 > 125$ is true because: $x > 5$ or $x > -5$ for $|x| > 5$

Given that:

$|x| > 5$

Split the inequality as follows:

$x > 5$ or $x > -5$

Take the cube of both sides

$x^3 > 5^3$ or $x^3 > -5^3$

Evaluate all exponents

$x^3 > 125$ or $x^3 > -125$

Steven's conjecture that: $x^3 > 125$ is true because:

$x > 5$ or $x > -5$ for $|x| > 5$

Read more about absolute inequalities at:

brainly.com/question/4688732

5 0

3 years ago