For f(x) = 2|x+3| – 5, name the type of function and describe each of the three transformations from the parent function f(x) =
2 answers:
Answer:
<h2>Shifted 5 units down</h2><h2>Shifted 3 units to the left</h2><h2>Vertically streched by a scale of 2.</h2>Step-by-step explanation:
The parent function is
The transformed function is
You can deduct by comparison, that the function was shifted 5 units down, 3 units to the left, and vertically streched by a scale of 2.
We deduct this transfromations based on the following rules.
indicates a movement downside
units.
indicates a movement leftside
units.
indicates a vertical stretch for
.
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Answer:
Step-by-step explanation:
From the table;
When x=2,
When x=3,
When x=4,
We can infer from the pattern that;
Refer to the diagram shown below.
When the two forces F₁ and F₂ are added vectorially, the resultant force is R.
The angle x = 180° - 50° = 130°.
From the Law of Cosines, obtain
R² = F₁² + F₂² - 2F₁F₂ cos(130°)
Note that 2 cos(130°) = -1.2856.
Answer:
R = √(F₁²+ F₂² + 1.2856 F₁F₂ )
When the two forces F₁ and F₂ are added vectorially, the resultant force is R.
The angle x = 180° - 50° = 130°.
From the Law of Cosines, obtain
R² = F₁² + F₂² - 2F₁F₂ cos(130°)
Note that 2 cos(130°) = -1.2856.
Answer:
R = √(F₁²+ F₂² + 1.2856 F₁F₂ )