Question

What is the slope of the line threw (-9,6) and (-3, 9)

Answer 1

Hey!

The formula for finding slope is: $\frac {y_2-y_1} {x_2-x_1}$ or $\frac{difference\ in\ y}{difference\ in\ x }$

y₂ = 9

y₁ = 6

9 - 6 = 3

x₂ = -3

x₁ = -9

(-9) - (-3) = 6

That gives you: 3/6 = -1/2

$\framebox{Slope = \dfrac{1}{2} }}$

Answer 2

Slope = (y2-y1)/(x2 - x1)

Slope = (9 - 6)/(-3- (-9)) = 3/6 = 1/2

Answer: 1/2