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Salsk061 [2.6K]
3 years ago
11

Find the zeros of the function in the interval -2 pi 2 pi

Mathematics
1 answer:
beks73 [17]3 years ago
4 0

Answer:

22 pi

Step-by-step explanation:

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1 Point<br> The circle below is centered at (-3, 2) and has a radius of 3. What is its<br> equation?
arlik [135]

Answer:

(x + 3)^2 + (y - 2)^2 = 9

Step-by-step explanation:

<u>Equation for a circle:  (x – h)^2 + (y – k)^2 = r^2</u>

<u />

<u>Step 1:  Determine what h, k, and r are</u>

<em>h is the x value of the point:  -3</em>

<em>k is the y value of the point:  2</em>

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<u>Step 2:  Plug in and solve</u>

(x – h)^2 + (y – k)^2 = r^2

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<em>(x + 3)^2 + (y - 2)^2 = 9</em>

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Answer:  (x + 3)^2 + (y - 2)^2 = 9

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3 years ago
Solve. 4.75t + 5 = 13.5t + 12 The solution is t = .
Eddi Din [679]
Answer: t= -0.799
This can also be written as t= -0.8

How to do it :

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first, subtract 4.74t from both sides
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next, subtract 12 from each side
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next, divide 8.76 from each sides

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