Answer:
csc(-112°)=-csc(68°)
Step-by-step explanation:
Since cosec(x) and sin(x) are reciprocals of each other,
cosec(-112°)=
=
=
(since 112=180-68)
=
(since sin(180-x)=sinx)
=
(since 
)
=-cosec(68°)
Answer:
R''(2, 1), S''(-1, 7), T''(2, 7)
Step-by-step explanation:
Rotation 90° CCW is accomplished by the transformation ...
(x, y) ⇒ (-y, x)
Translation 3 left and 8 up is accomplished by the transformation ...
(x, y) ⇒ (x -3, y +8)
Together, the two transformations give ...
(x, y) ⇒ (-y -3, x +8)
So your transformed points are ...
R(-7, -5) ⇒ R''(-(-5)-3, -7+8) = R''(2, 1)
S(-1, -2) ⇒ S''(-(-2)-3), -1+8) = S''(-1, 7)
T(-1, -5) ⇒ T''(-(-5)-3, -1+8) = T''(2, 7)
Answer:
a
Step-by-step explanation:
Answer:
0_10 =0_2
Step-by-step explanation:
Convert the following to base 2:
0_10
Hint: | Starting with zero, raise 2 to increasingly larger integer powers until the result exceeds 0.
Determine the powers of 2 that will be used as the places of the digits in the base-2 representation of 0:
Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value
0 | 2^0 | 1
Hint: | The powers of 2 (in ascending order) are associated with the places from right to left.
Label each place of the base-2 representation of 0 with the appropriate power of 2:
Place | | | 2^0 |
| | | ↓ |
0_10 | = | ( | __ | )_(_2)
Hint: | Divide 0 by 2 and find the remainder. The remainder is the first digit.
Determine the value of 0 in base 2:
0/2=0 with remainder 0
Place | | | 2^0 |
| | | ↓ |
0_10 | = | ( | 0 | )_(_2)
Hint: | Express 0_10 in base 2.
The number 0_10 is equivalent to 0_2 in base 2.
Answer: 0_10 =0_2
15ft per sec would be the unit rate.
