Answer:
The amount of money that should be invested at the rate of 12% is $900 and the amount of money that should be invested at the rate of 10% is $2,100
Step-by-step explanation:
Let
x ------> the amount of money that should be invested at the rate of 12%
3,000-x -----> the amount money that should be invested at the rate of 10%
we know that
The sum of the interest on each of the accounts must be equal to the total interest.
Solve for x
therefore
The amount of money that should be invested at the rate of 12% is $900 and the amount of money that should be invested at the rate of 10% is $2,100
Hope this helps you!!!! :D
Answer: x=-12
Step 1: Simplify both sides of the equation.
4x+27=−33−x
4x+27=−33+−x
4x+27=−x−33
Step 2: Add x to both sides.
x+27+x=−x−33+x
5x+27=−33
Step 3: Subtract 27 from both sides.
5x+27−27=−33−27
5x=−60
Step 4: Divide both sides by 5.
x=−12
Since we know a circle has 360 degrees, the sector bounded by a 90 degree arc will be a quarter of circle (360/90 = 4). Then, to calculate the area of that sector, we can calculate the total area of the circle of radius 10, and then divide it by 4.
The area of a cirlce of radius r is:
Then, the area of the sector would be:
Answer: P = $ 1,998.01
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 24%/100 = 0.24 per year,
putting time into years for simplicity,
1 months ÷ 12 months/year = 0.083333 years,
then, solving our equation
P = 39.96 / ( 0.24 × 0.083333 ) = 1998.007992032
P = $ 1,998.01
The principal required to
accumulate interest of $ 39.96
on a rate of 24% per year for 0.083333 years (1 months) is $ 1,998.01.
Answer:
14.4
Step-by-step explanation:
