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2 years ago

PLS HELP ILL MARK BRAINLEST PLUS ADDITIONAL POINTSS!!

Mathematics

2 answers:

Serga [27]2 years ago

7 0

Answer:

114

Step-by-step explanation:

15 x 2 + 9 x 2 + 11 x 3 + 11 x 3 = 114

(the bottom portion is equal to 3 x 11)

SpyIntel [72]2 years ago

3 0

11 plus 9 plus 11 is 31.

31 plus 15 plus 15 is 61.

61 plus 11 plus 11 is 83.

83 plus 9 plus 9 is 101.

13 minus 9 is 4.

So the answer is C 114 mm.

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Rewrite 9cos 4x in terms of cos x.

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
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as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
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$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
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2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
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$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
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2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}$

4 0

2 years ago

3(12)=2(y-1) *plzz answer my question*

Leona [35]

Step-by-step explanation:

3(12)=2(y-1)

36=2y-2

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y=19

7 0

2 years ago

Which transformations will produce similar, but not congruent, figures?

n200080 [17]

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7 0

2 years ago

Read 2 more answers

Which property of operation could you use to show whether 7y + 7b + 3y and 7(y x b) + 3b are equivalent or not

Dmitry_Shevchenko [17]

Answer and explanation:

They are not equivalent because if we simplify the second expression, the result isn't the same:

7(y×b)+3b

= 7(yb)+3b

=7yb + 3b

Therefore 7yb+3b≠7y+7b+3y

And even though you meant

7(y+b)+3b

=7y+7b+3b

=7y+10b

7y+10b≠10y+7b

5 0

2 years ago

(X8.6.PS-12

Andrew [12]

Answer:

area = 138 m²

Step-by-step explanation:

radius of large circle = 12 m

radius of small circle = 10 m

large circle area = πr² = (3.14)(12²) = 452.16 m²

small circle area = πr² = (3.14)(10²) =314 m²

452.16 - 314 = 138.16 m²

7 0

2 years ago