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Alenkasestr [34]
3 years ago
12

LAS1. A city government spends $1,860,000 a month on public services. Of that amount,46 percent is used for fire and police prot

ection.A) How much is spent bach month for fire and police protection?B) How much is spent by the city in a year for fire and police protection?1. In a city in which there are 90,000 employed workers, 18,000 are publicemployees. Of this number, the federal government employs 6,000; the state, 8,000, andthe city, 4,000.A) What percentage of all workers are public employees?B) What percentage of the public employees does the federal government employ?​
Business
1 answer:
Nookie1986 [14]3 years ago
8 0

Explanation:

The computation is shown below:

(A) For amount spent by the city in a year for fire and police protection is

= $1,860,000 × 0.46%

= $855,600

(B) For amount spent yearly  for fire and police protection is

= $855,600 × 12 months

= $10,267,200

(A) The percentage of public employees is

Percentage of public employees = (Public employees ÷ Total employed workers) × 100

= (18,000 ÷ 90,000) × 100%

= 20%

(B) Now for federal government employ percentage

= (Federal government employees ÷ Public employees) × 100

= (6,000 ÷ 18,000) × 100%

= 33.33%

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The purpose of this media message is to inform people that they have the opportunity to save money. Thus, option B is correct.

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Which of the following is a true statement?
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The manager of a computer software company wishes to study the number of hours senior executives by type of industry spend at th
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Answer:

Since the calculated value of F= 5.733 falls in the critical region we reject the null hypothesis  and conclude all three means are not equal.

Explanation:

The given data is

Banking          Retail            Insurance

12                      8                        10

10                     8                          8

10                     6                          6

12                     8                           8

<u>10                    10                          10</u>

The results of excel are:            

<u><em>Anova: Single Factor  </em></u>    

     

SUMMARY      

Groups    Count Sum Average         Variance  

Column 1 5 54            10.8              1.2  

Column 2 5 40               8               2  

Column 3 5 42              8.4                 2.8  

         

1) Let the null and alternate hypotheses be

H0: u1=u2=u3  i.e all the three means are equal and

Ha: Not all three means are equal

2) The significance level is set at ∝ =0.05

3)The test statistic to use is

F= sb²/ sw²

which has F distribution with v1= k-1 →3-1=2 and v2= n-k →15-3=12 degrees of freedom

After calculations the following table is obtained.

<u><em>ANOVA  </em></u>    

Source              SS            df         MS            F        P-value        F crit

of Variation

B/w Groups        22.93         2     11.467      5.733    0.01788        3.885

<u>Within Groups       24           12           2                                                       </u>      

<u>Total                     46.93      14                                                                </u>

4) The critical region is F ≥ F(0.05, 2,12) = 3.885

5) Since the calculated value of F= 5.733 falls in the critical region we reject the null hypothesis  and conclude all three means are not equal.

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