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vampirchik [111]
3 years ago
5

64 is 4 times the difference between Sarah's age, a, and 44. Assume Sarah is older than 44.

Mathematics
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

1. 4(a-44) = 64

2. Sarah is 60 years old

Step-by-step explanation:

Given that 64 is 4times the difference between a and 44 and she is older than 44:

1.

4(a-44) = 64

Next is solve,

2.

4(a-44) = 64

a - 44 = 16

a = 60

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The sum of two trinomials is 7x2 - 5x + 4. if one of the trinomials is 3x2 + 2x - 1, then what is the other trinomial?
Margarita [4]

Answer:

  b.  4x^2 -7x +5

Step-by-step explanation:

When you know a sum and one of its contributors, you can find the other by subtraction. The other trinomial is ...

  (7x^2 -5x +4) - (3x^2 +2x -1)

  = (7 -3)x^2 +(-5 -2)x +(4 -(-1))

  = 4x^2 -7x +5 . . . . . matches B

5 0
2 years ago
The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi
yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let p_1 = <u><em>percentage of employed workers who have registered to vote.</em></u>

p_2 = <u><em>percentage of unemployed workers who have registered to vote.</em></u>

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, H_A : p_1>p_2     {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

                          T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of employed workers who have registered to vote = \frac{287}{513} = 0.56

\hat p_2 = sample proportion of unemployed workers who have registered to vote = \frac{280}{604} = 0.46

n_1 = sample of employed persons = 513

n_2 = sample of unemployed persons = 604

So, <u><em>the test statistics</em></u>  =  \frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }

                                       =  3.349

The value of z test statistics is 3.349.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

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Absolute value can never be negative
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| 1 | ( ) 5

1 ( ) 5
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