Answer:
![14878.04878miles/hours^2](https://tex.z-dn.net/?f=14878.04878miles%2Fhours%5E2)
Step-by-step explanation:
Let's find a solution by understanding the following:
The acceleration rate is defined as the change of velocity within a time interval, which can be written as:
where:
A=acceleration rate
Vf=final velocity
Vi=initial velocity
T=time required for passing from Vi to Vf.
Using the problem's data we have:
Vf=65miles/hour
Vi=6miles/hour
T=14.8seconds
Using the acceleration rate equation we have:
, but look that velocities use 'hours' unit while 'T' uses 'seconds'.
So we need to transform 14.8seconds into Xhours, as follows:
![X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)](https://tex.z-dn.net/?f=X%3D%2814.8seconds%29%2A%281hours%2F60minutes%29%2A%281minute%2F60seconds%29)
![X=0.0041hours](https://tex.z-dn.net/?f=X%3D0.0041hours)
Using X=0.0041hours in the previous equation instead of 14.8seconds we have:
![A=(65miles/hour - 6miles/hour)/0.0041hours](https://tex.z-dn.net/?f=A%3D%2865miles%2Fhour%20-%206miles%2Fhour%29%2F0.0041hours)
![A=(61miles/hour)/0.0041hours](https://tex.z-dn.net/?f=A%3D%2861miles%2Fhour%29%2F0.0041hours)
![A=(61miles)/(hour*0.0041hours)](https://tex.z-dn.net/?f=A%3D%2861miles%29%2F%28hour%2A0.0041hours%29)
![A=61miles/0.0041hours^2](https://tex.z-dn.net/?f=A%3D61miles%2F0.0041hours%5E2)
![A=14878.04878miles/hours^2](https://tex.z-dn.net/?f=A%3D14878.04878miles%2Fhours%5E2)
In conclusion, the acceleration rate is ![14878.04878miles/hours^2](https://tex.z-dn.net/?f=14878.04878miles%2Fhours%5E2)
X^2 +mx +m = (x+2 )^2
since (x+2)^2 = x^2 +2(2x) + 2^2
= x^2 + 4x + 4
therefore the answer is m= 4
C
The sum of dots of the dice is
1+2+3+4+5+6=21
21 dots in a dice
If you understand please like and follow me
5*n-4=26
26+4=30
30 divided by 5 =6
answer : 6